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pychu [463]
2 years ago
8

What is the value of n in the equation 1/2(n-4)-3=3-(2n+3) ?

Mathematics
2 answers:
svp [43]2 years ago
8 0
The answer to this question is n=2
bulgar [2K]2 years ago
5 0

Answer:

2

Step-by-step explanation:

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20

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2 years ago
dexamethasone 4 mg/1 ml is available. the MD orders 6000 mcg. how much will the nurse give? (Round to the tenth)​
aleksley [76]

Answer:

  1.5 mL

Step-by-step explanation:

The abbreviation mcg stands for "microgram," or 10^-6 grams. The abbreviation mg stands for "milligram," or 10^-3 grams. The relationship between these is ...

  1 mg = 1000 mcg

<h3>Dose</h3>

The order for 6000 mcg is an order for 6(1000 mcg) = 6(1 mg) = 6 mg. At 4 mg/mL, the quantity of dexamethasone required is ...

  (6 mg)/(4 mg/mL) = (6/4) mL = 1.5 mL

The nurse will give 1.5 milliliters of dexamethasone.

4 0
1 year ago
The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f
Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen  who carry a credit card balance.

The formula for the interval is:

p'₁±Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }

Z_{1-\alpha /2}= Z_{0.95}= 1.648

0.37±1.648*\sqrt{\frac{0.37*0.63}{1000} }

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂±Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }

0.48±1.648* \sqrt{\frac{0.48*0.52}{1000} }

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: \sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015

Seniors: \sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0
3 years ago
MAT-1101-3 - ARITHMÉTIQUE APPLIQUÉE AUX FINANCES
Doss [256]

Answer:

B ignore bottom

Step-by-step explanation:

Your answer should be written in paragraph/essay format.

Any sources used should be cited at the bottom of your paper.

All answers should show you have learned something from Unit 9.  Material from other units will not be graded for this assignment.

If you are stuck, you can think about the following topics: textile mills, interchangeable parts, the Lowell System, unions, labor reform, steamboats, railroads, coal, the telegraph, and/or new inventions.

8 0
2 years ago
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