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Ivanshal [37]
2 years ago
12

Hey, can someone help me with this question?

Mathematics
1 answer:
aleksley [76]2 years ago
7 0

Step-by-step explanation:

A = P(1 + r)^t

£5263.73 = £4000(1 + 0.01x)^7

(1 + 0.01x)^7 = 1.3159325

1 + 0.01x = 1.04

0.01x = 0.04

x = 4.

The value of x is 4.

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Change each of the following angles in degrees to angles in radians
grin007 [14]

Answer:

d: 2.6179, e: 4.1887, f: 5.2359 all in rad

Step-by-step explanation:

(d): 150°degrees

150° × π / 180°

= 0.83333333333π rad

= 2.6179 rad

(e):240°degrees

240° × π / 180°

= 1.3333333333π rad

= 4.1887 rad

(f): 300°degrees

300° × π / 180°

= 1.6666666667π rad

= 5.2359 rad

If all my stuff is correct please give me an 5/5 and a thanks. :)

7 0
3 years ago
solve quadratic by taking square roots. as=a,-a where a and -a the values you found when when solving. Round to nearest tenth. 2
attashe74 [19]

Answer:

8.1

Step-by-step explanation:

2x^2 -9 = 121

        +9    +9

2x^2 = 130

/2         /2

x^2   = 65

x= sqrt (65)

x= 8.06225...

x = 8.1

6 0
3 years ago
Analyze the diagram below and complete the instructions that follow.
lapo4ka [179]

Answer:

I've looked at this over and over  the answer it's yes.

Step-by-step explanation:

3 0
3 years ago
The lines 2x=ky+2 and (k+1)x=6y-3 have same gradient. Find possible values of k
faust18 [17]

Answer:

k = 3 or k = -4

(Anyone can correct me if I'm wrong)

Step-by-step explanation:

2x=ky+2\to\ eq1\\(k+1)x=6y-3\to\ eq2\\$Change to this form: $y=mx+c\\ky=2x-2\\y=\frac{2x-2}{k}\\$gradient of eq1: $\frac{2}{k}\\6y=(k+1)x+3\\y=\frac{(k+1)x+3}{6}\\y=\frac{k+1}{6} x+\frac{3}{6}\\y= \frac{k+1}{6} x+\frac{1}{2}\\$gradient of eq1: $\frac{k+1}{6}\\$Since gradient, m, is the same for both lines,$\\\frac{2}{k}=\frac{k+1}{6}\\12=k^{2}+k\\k^{2}+k-12=0\\(k-3)(k+4)=0\\k=3 $ or $ k=-4

6 0
2 years ago
Please educated people solve my question.. i asked it an hour ago nobody knows it
Mazyrski [523]

AB = AX+XB = 6+18 = 24

The ratio of AB to AX is AB/AX = 24/6 = 4

AC = AY+YC = 10+25 = 35

The ratio of AC to AY is AC/AY = 25/10 = 3.5

The results of each division are 4 and 3.5

We do <u>not</u> get the same result, which means that the proportion \frac{AB}{AX} = \frac{AC}{AY} is <u>not</u> true. This is sufficient to prove that the triangles aren't similar. We need them to be in proportion so that we can use the SAS similarity rule.

<h3>Answer: The triangles aren't similar</h3>
8 0
2 years ago
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