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3 years ago

Is a vertical line perpendicular to the x-axis

Mathematics

2 answers:

marshall27 [118]3 years ago

6 0

Yes it is perpendicular to the x axis

borishaifa [10]3 years ago

5 0

A vertical line is perpendicular to the x-axis because they would intersect to form a 90 degree angle.

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6 1/42 + 4 5/6= simplest form + show work.

marissa [1.9K]

Answer:

1. 10 6/7 2. 8/15

Step-by-step explanation:

1. 6 1/42 + 4 5/6

First, let's combine the whole numbers. 6 + 4 = 10

Now we are left with 1/42 + 5/6.

To add or subtract, the dominators need to be the same. We need to find the least common multiple which here is 42.

1/42 + 5/6(7)

1/42 + 35/42

= 36/42

= 6/7

All we have to do is combine both numbers.

10 6/7

2. 13/15 - 1/3(5)

13/15 - 5/15

8/15

6 0

3 years ago

John needs 7 gallon bottles of water to fill 90water balloons how many gallon bottles of water does John need to purchase to fil

Allushta [10]

Answer:

11 bottles

Step-by-step explanation:

make a proportion because if you're using the same rate proportions can show that it's equal

$\frac{7}{90} = \frac{x}{140}$

cross multiply

$7 *140$ $= 980$

divide the answer by 90 to find x

$980/90= 10.8$

round to 11 because you can't have 10.8 bottles

8 0

3 years ago

Find the surface area of a rectangular prism that has the following dimensions.

faltersainse [42]

2(wl+hl+hw)=2·(6·4.5+12·4.5+12·6)=306

3 0

3 years ago

Read 2 more answers

Drag each coordinate pair to the correct location on the table. Each coordinate pair can be used more than once, but not all coo

Tasya [4]

Answer:

For inequation 1:

(2, 6)(1, -3)(-2, 5)

For inequation 2:

(2, 6)(-1,-1)(-3. 4)(1,-3)

For the system:

(2, 6)(1, -3)

Step-by-step explanation: got it right on the test

4 0

2 years ago

What is the interquartile range of the data?<br><br> I think the answer is B.

zhenek [66]

Answer:

No, correct option is (A) 117.5

Step-by-step explanation:

Interquartile range (IQR) measures the skewness using 50% of the data. It is the difference between the third quartile and the first quartile. i.e.

IQR = Q₃ - Q₁

For finding the Interquartile Range of the data:

100, 120, 130, 188, 196, 220, 265, 300

Divide the data into two parts:

(100, 120, 130, 188) (196, 220, 265, 300)

2. Now finding the medians of both halves of the data that will be our First and Third Quartile of data.

So, Q₁ = 125 and Q₃ = 242.5

Now, using IQR = Q₃ - Q₁

= 242.5 - 125 = 117.5

Hence, Correct option is Option (A).

4 0

3 years ago