You have two angles congruent, plus a side that's NOT between them.
I guess you'd call that situation " AAS " for "angle-angle-side".
That's what you have, and it's NOT enough to prove the triangles
congruent. There can be many many different pairs of triangles
that have AAS = AAS.
So there's no congruence postulate to cover this case, because they're
not necessarily.
The slope is 2/3 you’re welcome :)
Answer:
x=-3,x1/2
Step-by-step explanation:
f(x)=(2x-1)(x+3)
TI find x intercept/zero substitute
f(x)=0
0=(2x-1)x(x+3)
swap the sides of the equation
(2x-1)x(x+3)=0
when the product of factors equals 0,at least one factor is zero
2x-1=0
x+3=0
solve the equation for x
x=1/2
x+3=0
solve the equation of x
x=-3
The equation has two solution
x=-3
x=1/2
Answer:
Option D is the correct option.
<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em><em>.</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>