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scoray [572]
2 years ago
8

What is the difference 1/8 - 3/10 a.17/40 b.7/40 c.-3/40 d.7/40

Mathematics
1 answer:
UNO [17]2 years ago
8 0

Answer:

c

Step-by-step explanation:

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CAN ANYONE HELP ME PLS I NEED HELP PLS AND THANK YOU
ch4aika [34]

Answer:

Here, BRX and NJY are two triangles in which,

Step-by-step explanation:

4 0
2 years ago
The area of a rectangular horse pasture is 268,500 square yards. The length of the pasture is 5 yards less than three times the
Setler79 [48]

Answer:  width = 300

<u>Step-by-step explanation:</u>

Area (A) = Length (L) x width (w)

Given: A = 268,500

           L = 3w - 5

           w = w

268,500 = (3w - 5) x (w)

268,500 = 3w² - 5w

            0 = 3w² - 5w - 268,500

            0 = (3w + 895) (w - 300)

   0 = 3w + 895        0 = w - 300

  -985/3 = w             300 = w

Since width cannot be negative, disregard w = -985/3

So the only valid answer is: w = 300

   

8 0
3 years ago
Which rule deacribes the
Marysya12 [62]

Answer:

A. {T_{-6,-2}}\circ {r_{x-axis}}(x,y)

Step-by-step explanation:

We have that, ΔABC is transformed to get ΔA''B''C''.

We see that the following transformations are applied:

1. Reflection across x-axis i.e. flipped across x-axis.

Now, ΔABC is reflected across x-axis along the line AC to get ΔA'B'C'.

2. Translated 2 units down i.e. shifted 2 units down and and then translated 6 units to the left i.e. shifted 6 units to the left.

So, ΔA'B'C' is translated 2 units downwards and 6 units to the left to get ΔA''B''C''.

Hence, the sequence of transformations is Reflection across x-axis and then Translation of 2 units down and 6 units left.

6 0
3 years ago
What is the side length, in inches, of the pets
tatiyna

Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer and asks for a sign that has an area of 16x2 – 40x + 25 square inches. What is the side length, in inches, of the pet shop sign?

Answer:

the length of the sign is 4x-5 inches

Step-by-step explanation:

Given

Area of the square of design = 16x^{2} -40x+25

First we find the roots of equation 16x^{2} -40x+25=0

The roots of the quadratic equation ax^{2} +bx^{2} +c=0 are given by

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a=16, b=-40, c=25

x=\frac{40\pm\sqrt{(-40)^2-4\times 16\times 25}}{2\times 16}

x=\frac{40\pm\sqrt{1600-1600}}{32}

x=\frac{40\pm\sqrt{0}}{32}

x=\frac{40}{32}

x=\frac{5}{4}

4x=5\\4x-5=0

That is, the factors of the polynomial 16x^{2} -40x+25 are 4x-5 and 4x-5.

So, Area of the square design = 16x^{2} -40x+25 = (4x-5)^{2}

Area of a square = Length^2

Thus, the length of the sign is 4x-5 inches

7 0
3 years ago
For an angle θ with the point (−5, −12) on its terminating side, what is the value of cosine?
viva [34]

Answer:

option C. -\frac{5}{13}

Step-by-step explanation:

we have  that

The point (-5,-12) belong to the III quadrant

so

The value of the cosine is negative

Applying the Pythagoras Theorem

Find the value of the hypotenuse

h^{2}=5^{2}+12^{2}\\ h^{2} =25+144\\ h^{2}=169\\h=13\ units

The value of cosine of angle θ is the ratio between the side adjacent to angle θ and the hypotenuse

cos(\theta)=-\frac{5}{13}

8 0
3 years ago
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