In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
Answer: The area is 13
ft^2 or 40.84 ft^2
Step-by-step explanation:
First find the area of the square and subtract it from the area of the circle.
The area of a square is one of the side length squared.
A= 6^2
A = 36
Now find the area of the whole circle.As it indicates that the diameter is 14ft and to find the area of a circle,we need square the radius and multiply it by pi.
Since the diameter is 14 divide it by 2 to find the radius. 14/2 = 7
A= 7^2*
A = 49
We will leave the area in terms of pi.
49
- 36 = 13
Answer:
f = 3 1/2
Step-by-step explanation:
f = 2t - 3f Substitute 7 for t
f = 2(7) - 3f Multiply
f = 14 - 3f
+3f + 3f Add 3f to both sides
4f = 14 Divide both sides by 4
f = 3 1/2
If this answer is correct, please make me Brainliest!
L=2W-4
PERIMETER=2L+2W
58=2(2W-4)+2W
58=4W-8+2W
58=6W-8
6W=58+8
6W=66
W=66/6
W=11 ANS. FOR THE WIDTH.
L=2*11-4
L=22-4
L=18 ANS. FOR THE LENGTH.
PROOF:
58=2*18=2*11
58=36+22
58=58
Answer:
The one you have selected is the right answer 126 times pi
Step-by-step explanation:
Exact answer - 395.840674