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3 years ago

Can you help me solve the system by substitution

Mathematics

1 answer:

Semenov [28]3 years ago

8 0

Answer:

The answer is (-36,6)

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

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Draw the segment PQ with endpoints P(-2, -1) and Q(2,4) on the coordinate plane. Then find the length and midpoint of PQ.

TiliK225 [7]

The graph of the line segment PQ is attached. To find the length, we have to use distance formula which is

$d = \sqrt{ (x_{2} -x_{1} )^2 + (y_{2} - y_{1} )^2 }$

$PQ = \sqrt{ (2-(-2))^2 + (4- (-1))^2 } = \sqrt{ (2+2)^2 + (4+1)^2 }$

$PQ = \sqrt{16+25} = \sqrt{41}$

To find the midpoint,we have to use the formula

$( \frac{x_{1}+ x_{2} }{2} ,\frac{y_{1}+ y_{2} }{2} ) = (\frac{-2+2}{2} , \frac{-1+4}{2} )$

$= ( \frac{0}{2} , \frac{3}{2} ) = (0 , \frac{3}{2} )$

4 0

4 years ago

Multiply and simplify. 2x2y3z2 · 4xy4x2 how to do?

Darya [45]

Answer:

$\huge\boxed{8x^5y^7z^2}$

Step-by-step explanation:

$\text{Use}\ a^n\cdot a^m=a^{n+m}\\\\2x^2y^3z^2\cdot4xy^4x^2=(2\cdot4)(x^2xx^2)(y^3y^4)z^2=8x^{2+1+2}y^{3+4}z^2\\\\=8x^5y^7z^2$

6 0

4 years ago

PLEASE HELP WILL GIVE BRAINLIEST

Olin [163]

Answer:

Step-by-step explanation:

in tri ADC and tri BDC

∠ADC =∠BDC = 90

DC is common

AD = BD (given)

triangle ADC ≅ tri BDC by SAS congruency

hence AC = BC by CPCT ( congruent parts of congruent triangles)

hence, BC = 13

8 0

4 years ago

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If Serena selects 4 samples from the table, which row

defon

Answer: 1: row 3

2: Row 2

3: 6 and 10

Step-by-step explanation:I just did it

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4 years ago

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For what value of X-1/3x=12

vovangra [49]

Answer:

Step-by-step explanation:

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4 years ago