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rewona [7]
3 years ago
7

If f(x) = 3x + 2, what is f(5)?​

Mathematics
2 answers:
Helen [10]3 years ago
7 0

Answer:

17

Step-by-step explanation:

3(5) + 2 = 17

15 + 2 = 17

MrRa [10]3 years ago
5 0

Answer:

f(5) = 17

Step-by-step explanation:

plug in 5 in the x so 3(5)+2 =17

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I drew it out. Hope this helps.

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3 years ago
What is an equation of the parabola with vertex at the origin and focus (0, 0.75)?
morpeh [17]

Answer:

x^{2} =3y

Step-by-step explanation:

Notice that the focus is a points on the vertical axis, that means the parabolla opens vertically, and has the form

x^{2} =4py

Because the parameter p is positive and equal to 0.75. Additionally, the vertex is at the origin, that's why the equation is this simple.

Replacing the parameter value, we have

x^{2} =4(0.75)y\\x^{2} =3y

Therefore, the equation of a parabolla with vertex at the origin and focus at (0, 0.75) is x^{2} =3y.

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3 years ago
1) Madison went shopping and spent $125 she paid $45 in Texas what was the sale tax rate (percent)
Gnesinka [82]

Answer:

170

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3 0
3 years ago
Simplify 6 - 2 3 + (-9 + 5) · 2.
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Answer: -25

Hope this helps! <3
4 0
3 years ago
Read 2 more answers
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
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