Lizette ran for 1.25 hours and walked for 3 hours.
distance = speed × time
Her total distance is the sum of her distances at the different speeds. Let w represent her walking speed in mi/h. For distances in miles, speeds in miles per hour, and time in hours, the problem statement tells us ...
19 = (w+5)(1.25) + (w)(3)
19 = 4.25w + 6.25 . . . . collect terms
12.75 = 4.25w . . . . . . . subtract 6.25
3 = w . . . . . . . . . . . . . . . divide by 4.25
Lizette's walking speed is 3 mph.
Lizette's running speed is 8 mph.
The steps i took into doing these problems did very well for me
Answer: 28.8°
<u>Step-by-step explanation:</u>
∠A = 5(∠B) + 7.2°
∠B = ∠B
Since they are on a straight line, they form a linear pair (sum = 180°)
∠A + ∠B = 180°
Use Substitution:
5(∠B) + 7.2° + ∠B = 180°
Add like terms:
6(∠B) + 7.2° = 180°
Subtract 7.2° from both sides:
6(∠B) = 172.8°
Divide both sides by 6:
∠B = 28.8°
Answer:
1
Step-by-step explanation:
Answer:
The probability that a worker makes between $400 and $450 is .3413 using the calculator and .34 using the empirical rule.
Step-by-step explanation:
There are two ways to approach this problem.
The first way is to find the <u>z-score</u> corresponding to $400 and $450 weekly wage and find the p-value in between these values.
If you use the normalcdf function on your calculator and put 0 and 1 as the lower and upper bounds, respectively, you will get an area of .3413.
Another way of looking at this problem is to recognize that the weekly wages given are the mean and one standard deviation above the mean.
We can use the <u>Empirical Rule</u>, <em>68-95-99.7</em>, in order to see that going one standard deviation above the mean would be an area of 68/2 = .34.
I've attached an image that shows you what the normal curve looks like.