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3 years ago

Chris wants to order blu-rays over the internet. Each Blu-ray cost $29.99 and shipping for

Mathematics

1 answer:

astra-53 [7]3 years ago

4 0

Answer:

4 blu-rays

Step-by-step explanation:

*Note: I'm rounding up to full dollars to make this easier. You will get the same answer, whether you round up or not.

First, get rid of the shipping cost from the budget.

$150 - $10 = $140 left for blu-rays

Then divide $140 by $30, which is the price for a single blu-ray to get the number of blu-rays Chris can get.

$140 ÷ $30 ≈ 4.6 repeating. You can't have a fraction of a movie, so Chris can get 4 blu-rays

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sergiy2304 [10]

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Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

Sorry I need help with these 3! Thank you to whoever takes the time to solve them!!!

mash [69]

1.)
Starts with 40:10, then cuz you have 80 buns, you need to x2, so it would be 20 cubes

2.)
I don’t know, sorry

3.)
4:2 and 60 in total
so 4+2 is 6 and 60/6 is 10
so it would be 40:20 so 20

hope this helps :)

8 0

3 years ago