-5x + 11 __) Please show your work!

Solve and graph the inequality on a number line -19>g-24

Lorico [155]

Do, 24 + -19

= 5

-19 > 5

-19 is bigger than 5

So the answer is
g = 5

7 0

3 years ago

The length of a pole is to be 6.5ft. The actual length of the pole may vary by as much as 0.02ft. Write an absolute value inequa

Airida [17]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

|x - 6.5| < 0.02 ft is the <span>absolute value inequality for the possible lengths of the pole.</span>

7 0

3 years ago

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

3 years ago

What is the scale factor when a larger image Q has an area of 36 square units and the smaller version has an area of 9 square un

schepotkina [342]

Answer:

6

Step-by-step explanation:

scale factor means the amount of times you need to multiply

so,

36/9

=6

5 0

2 years ago

X-3<9<br><br> What’s the answer to this everbody should know

Murrr4er [49]

Answer:

x<12

Step-by-step explanation:

Let's solve your inequality step-by-step.

x−3<9

Step 1: Add 3 to both sides.

x−3+3<9+3

x<12

Answer:

x<12

5 0

3 years ago