Remember these two combinations: logab=loga+logb, log(a/b)=loga-logb
3logx=logx^3
(1/2)log(x+2)=log(x+2)^(1/2)
2log(z-4)=log(z-4)^2
so the given expression can be combined into log{[(x^3)(z-4)^2]/(x+2)^(1/2)}
Bro i did the same test [i picked c. for my answer]
Answer:
Step-by-step explanation:
so you have to multiply the ratio first
Answer:
The square cake is has a larger area by about 40.73 square inches
Step-by-step explanation:
Find the area of the top of each cake.
The square cake has an area of 81 sq inches, ( length x width = Area, the
length is 9)
The round cake has an area of 16π, which is about 50.27 square inches
(A = πr², here r is 4, radius is half the diameter)
81 - 16π = 81 - 50.27 = 40.73 square inches
First, isolate y on one side to find some information about the graph.
3x+4y=-10
4y=-10-3x
y=(-10-3x)/4
Now find out the x and y intercepts of this equation;
(0)=(-10-3x)/4
4x0=-10-3x
0=-10-3x
3x=-10
x=-10/3 or -3.3333 (x-intercept)
y=(-10-3(0))/4
4y=-10
y=-10/4 or -5/2 = -2.5 (y-intercept)
Plot these points onto your graph and connect the lines.
I have attached a graph below, I'm sorry I couldn't do it on paper.
Hope I helped :)