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2 years ago

A 15 feet tree casts a shadow that is 8 feet long. What is the distance from the tip of the tree to the tip of it's shadow?

Mathematics

2 answers:

boyakko [2]2 years ago

8 0

Answer:

17 feet

Step-by-step explanation:

I used the Pythagorean theorem to answer this question.

a^2 + b^2 = c^2

15^2 + 8^2 = c^2

225 + 64 = c^2

289=c^2

c^2=289

c=√289

c=17 feet

GrogVix [38]2 years ago

6 0

Answer:

7 feet

I hoped that helped

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5. In the triangle ABC. M is the midpoint of [AB] and N is the midpoint of [CM].

sweet [91]

Answer:

N(2,3)

Step-by-step explanation:

According to the Question,

Given that, In the triangle ABC. M is the midpoint of AB and N is the midpoint of CM And A(-1, 3), B(7-3) and C(1,6).

Thus, For coordinates of N. first We have to find the Coordinate of M(x,y). As Given M is the Midpoint of A(-1, 3) and B(7-3).

Thus, M(x,y) = (-1+7)/2 , (3-3)/2 ⇒ M(3,0)

Now, As Given, N(a,b) is the Midpoint Of C(1,6) and M(3,0).

Thus. N(a,b) = (1+3)/2 , (6+0)/2 ⇒ N(2,3)

8 0

3 years ago

Games at a carnival cost $3. prizes awarded to winners cost $145.65. how many games must be played to make $50

stich3 [128]

Answer:

Step-by-step explanation:

3×1405 and $.65

8 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago

A gardener uses a coordinate grid to design a new garden. The gardener uses polygon WXYZ on the grid to represent the garden. Th

ValentinkaMS [17]

Answer:

A square

36 square yard.

Step-by-step explanation:

Given the following information:

W(3,3), X(-3,3), Y(-3,-3), and Z(3,-3)

So we need to graph those vertices and connect them in order.

(please have a look at the attached photo)

From the graph, it clear that the shape of the garden is a square.

Then, we need to calculate the length of the four sides

<u>Find the length of the side YZ. </u>

The length of side YZ = 3 + 3 = 6 yards because point Y and Z are on the same line y = -3 so we just need to find the distance between their x coordinate

<u>Find the length of the side WZ.</u>

The length of side WZ = 3 + 3 = 6 yards because point W and Z are on the same line x = 3 so we just need to find the distance between their y coordinate

=> the area of the square WXYZ:

= YZ*WZ

= 6*6

= 36 square yard.