Answer:
2100 meters
Step-by-step explanation:
<u><em>REMEMBER: 1 km = 1000 m</em></u>
2.1 km x 1000= 2100 meters
hope this helps ;)
The answer is: z² .
__________________________
Given: <span>(x÷(y÷z))÷((x÷y)÷z) ; without any specified values for the variables;
_______________________
we shall simplify.
___________________
We have:
__________
</span>(x÷(y÷z)) / ((x÷y)÷z) .
_____________________________________
Start with the first term; or, "numerator": (x÷(y÷z)) ;
_____________________________________
x ÷ (y / z) = (x / 1) * (z / y) = (x * z) / (1 *y) = [(xz) / y ]
_____________________________________
Then, take the second term; or "denominator":
_____________________________________
((x ÷ y) ÷z ) = (x / y) / z = (x / y) * (1 / z) = (x *1) / (y *z) = [x / (zy)]
_________________________________________
So (x÷(y÷z)) / ((x÷y)÷z) = (x÷(y÷z)) ÷ ((x÷y)÷z) =
[(xz) / y ] ÷ [x / (zy)] = [(xz) / y ] / [x / (zy)] =
[(xz) / y ] * [(zy) / x] ;
_______________________________________
The 2 (two) z's "cancel out" to "1" ; and
The 2 (two) y's = "cancel out" to "1" ;
______________________________________________
And we are left with: z * z = z² . The answer is: z² .
______________________________________________
The rate of flow outward through the hemisphere x² + y² + z² = 9, z >= 0 is zero.
Given that,
Seawater has a density of 1025 kg/m³ and moves at a constant velocity field defined by the equations v = yi + xj, where x, y, and z are measured in meters and the components of V are expressed in meters per second.
We have to find the rate of flow outward through the hemisphere x² + y² + z² = 9, z >= 0.
We know that,
v= yi + xj, and density = 1025 kg/m³
F=1025(yi + xj)
After solving the R(u,v) we get zero.
Therefore, the rate of flow outward through the hemisphere x² + y² + z² = 9, z >= 0 is zero.
To learn more about hemisphere visit: brainly.com/question/28770672
#SPJ4
<h2><u>hello</u></h2>
<h3>your question is how can u understand world problem</h3><h3 /><h3>
The very first thing is that read the question</h3><h3>
Reading the questions doesnt mean that just looking at it and staring but you should the question line by line. still if cant understand try to read in your own language</h3>
<h3>
And my suggestion is that before going for exam you should be well prepared all the world problem given in text and you can also refer to the net for extra questions. practice more and more as you can</h3><h3>
</h3><h3>
And when you are reading the word problems . your concepts should be clear like a diamond like you should know from which chapter it is etc </h3>
<h3><u>hope this helps</u></h3><h3><u>:)</u></h3>