The amount of the extra snow would a child need to take a snowball will be 636.71 cubic cm.
<h3>What is the volume of the sphere?</h3>
Let d be the diameter of the sphere.
Then the volume of the sphere will be
V = 1/6 πd³ cubic units
Then the amount of the extra snow would a child need to take a snowball with a diameter of 8 cm and increase its size to a snowball with a diameter of 12 cm will be
Amount of snow = 1/6 π x 12³ - 1/6 π x 8³
Amount of snow = 288 π - 85.33π
Amount of snow = 636.71 cubic cm
More about the volume of the sphere link is given below.
brainly.com/question/9994313
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Your two equations are at the top, in the box is what each variable represents. Below the box is total liters of the 15%, which is going to equal the total liters for 10% plus the total liters for 25%. Make your percentages into decimals. There’s a total of 30 liters so, x+y needs to equal 30. Isolate a variable, I chose y, you can do either or (isolating x would be more math). Y is going to equal 30-x, substitute that for the Y in the second equation, then you need to distribute 0.25 into 30-x. Then it’s simple math, subtract 7.50 from both sides, add like gets, divide both sides by -0.15, making x=20.
Answer:
68 feet
Step-by-step explanation:
Vertical motion model:
h = -16t² + vt + s
Given v = 64 and s = 4:
h = -16t² + 64t + 4
This is a parabola. The maximum of a parabola is at the vertex.
For y = ax² + bx + c, the vertex is at x = -b/(2a).
Therefore, the time to reach the maximum height is:
t = -64 / (2 × -16)
t = 2
And the maximum height is:
h = -16(2)² + 64(2) + 4
h = 68
So the Frisbee reaches a maximum height of 68 feet.
Answer:
Attached is the sketch
X-axis intersections:
(-3,0)
(0,0)
(1,0)
Points of inflection:
(-1,319,-2.881) Concave upward
(0.569,1.041) Concave downward
Step-by-step explanation:
Desmos (I'm not allowed to post the link, pls search it up) is a great help for these type of problems!
900/18=50
On average, 50 students rode each bus
Hope this helps!