D = sq.root of((x2 - x1)^2 + (y2 - y1)^2)
sq.root of 13 = sq.root of((x - (-2))^2 + (1 - 3)^2)
= sq.root of((x + 2)^2 + (-2)^2)
= sq.root of (x^2 + 4x + 4 + 4)
= sq.root of (x^2 + 4x + 8)
Now if we square both sides:
x^2 + 4x + 8 = 13
x^2 + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5 or x = 1
Answer:
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Step-by-step explanation:
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Answer:
D. du/dx = 2x
Step-by-step explanation:
Given to find dy/dx where;
Then when you let;
u=x²+2 and
Then
In u=x²+2 du/dx = 2x------------------------step 1
In e^4x, dv/dx = e^4x * d/dx (4x)
=e^4x *4 = 4e^4x------------------------------------step 2
Answer:
2 < x
Step-by-step explanation:
7-2(x + 2) <-4 - 3(1 - x)
Distribute
7 - 2x-4 < -4 -3 +3x
Combine like terms
3 -2x < -7+3x
Add 2x to each side
3 -2x+2x< -7+3x+2x
3 < -7+5x
Add 7 to each side
3+7 < -7+7+5x
10 < 5x
Divide each side by 5
10/ 5 < 5x/5
2 < x
3/4 as a number = 0.75
So 1.75 x d = 14
14/1.75 = d
14/1.75= 8
D = 8
