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il63 [147K]
4 years ago
5

What is p in this situation? if u answer correct ill mark you brainliest.

Mathematics
1 answer:
anyanavicka [17]4 years ago
7 0
The answer is p = - 1/12
It’s a fraction btw with a negative in front of it .
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<A and <B are complementary
gizmo_the_mogwai [7]

Answer:

<A = 62

Step-by-step explanation:

<A and <B add up to 90 degrees. Definition of Complementary.

<A + <B = 90

(6x - 4) + (x + 17) = 90

7x + 13 = 90

7x = 77

x = 11

<A = 6x - 4

<A = 6(11) - 4

<A = 66 - 4

<A = 62

3 0
3 years ago
Simplify 13 + 2 - 5 - 15 a -25 b -5 c 5
Neko [114]

Answer:

−5c5−15a−25b+10

Step-by-step explanation:

13+2−5−15a−25b−5c5

=13+2+−5+−15a+−25b+−5c5

Combine Like Terms:

=13+2+−5+−15a+−25b+−5c5

=(−5c5)+(−15a)+(−25b)+(13+2+−5)

=−5c5+−15a+−25b+10

Answer:

=−5c5−15a−25b+10

4 0
4 years ago
Read 2 more answers
Drag and drop the constant of proportionality into the box to match the table. If the table is not proportional, drag and drop "
Art [367]

Answer:

3

Step-by-step explanation:

look at the numbers, check how far apart they are.

6 0
3 years ago
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The ratio of cars to trucks passing the intersection of Reyes Adobe and TO Blvd is 7:2. If 108 vehicles pass this intersection,
Dahasolnce [82]

Answer:

84 cars

Step-by-step explanation:

the the ratio is 7 to 2. There were 108 vehicles. 108/ 9=12

12 x 7= 84.... or at least that's how I think of it.

6 0
3 years ago
Find all the zeros of 2x4+x3-14x2-19x-6 two of its zeros are -2 and -1
GalinKa [24]

Answer:

-2,\ -1,\ -\dfrac{1}{2},\ 3.

Step-by-step explanation:

Consider polynomial 2x^4+x^3-14x^2-19x-6.

If x=-2 is its zero, then you can divide the polynomial 2x^4+x^3-14x^2-19x-6 by x+2 and get

2x^4+x^3-14x^2-19x-6=(x+2)(2x^3-3x^2-8x-3).

If x=-1, then the polynomial 2x^4+x^3-14x^2-19x-6 can be rewritten as

2x^4+x^3-14x^2-19x-6=(x+2)(x+1)(2x^2-5x-3).

The quadratic polynomial has roots

x_{1,2}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot2\cdot(-3)}}{2\cdot 2}=\dfrac{5\pm \sqrt{25+24}}{4}=\dfrac{5\pm \sqrt{49}}{4}=3,-\dfrac{1}{2}.

Then the polynomial 2x^4+x^3-14x^2-19x-6 has zeros -2,\ -1,\ -\dfrac{1}{2},\ 3.



7 0
3 years ago
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