<h3>
Therefore they are perpendicular.</h3>
Step-by-step explanation:
A equation of line is
y =mx +c
Here the slope of the line is m.
Given equations are
x - 2y = 18
⇔-2y = -x +18
............(1)
and 2x + y = 6
⇔y = -2x +6 ............(2)
Therefore the slope of equation (1) is
= 
Therefore the slope of equation (2) is
= -2
If two lines are perpendicular, when we multiply their slope we get -1.
therefore,
=
. (-2) = -1
Therefore they are perpendicular.
3/8 + 1/16= 7/16
so it's c. 7/16
Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
Hope this helps!!! :)
Attached photo work is created by another brainly user named tallinn.
Click on this link to find his work and possibly more information of the answer. Thanks!
Hello!
The letter D is in the place for the upper quartile
To find this you have to find the median of the data
List the numbers from least to greatest
12, 18, 34, 55, 59, 68, 80, 80
The medians are 55 and 59
To get the median we take the average of these numbers
55 + 59 = 114
114 / 2 = 57
The median is 57
To find the upper quartile you find the median of the numbers higher than 57
List the numbers that are higher than 57 in the data
59, 68, 80, 80
Take the average of 68 and 80
68 + 80 = 148
148/2 = 74
The answer is 74
Hope this helps!