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defon
3 years ago
9

Clarissa analyzes a data set and finds that r=0.95 what is the coefficient of determination for her data set

Mathematics
1 answer:
asambeis [7]3 years ago
4 0
2.983 than divide it by 2
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Complete the identity. cos (alpha - beta)/cos alpha cos beta = ?
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I belive the answer to be b
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Which number is equivalent to the fraction 15 over 7?
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15/7 is approximately 2.143
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3 years ago
Question 8 of 10
Andreyy89

Median and IQR are the most appropriate measures of center and spread for this data set.

<h3>Why are Median and IQR the most appropriate?</h3>

Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:

  • Mean is affected by extreme values
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Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,

Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.

Therefore, Option B is correct.

Read more about measures of center

brainly.com/question/10610456

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5 0
2 years ago
Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or
WARRIOR [948]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$6000\\&#10;r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{quarterly, thus four}&#10;\end{array}\to &4\\&#10;t=years\to &4&#10;\end{cases}&#10;\\\\\\&#10;A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\&#10;-------------------------------\\\\



\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$6000\\&#10;r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{semiannually, thus two}&#10;\end{array}\to &2\\&#10;t=years\to &4&#10;\end{cases}&#10;\\\\\\&#10;A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8

compare them away.
4 0
3 years ago
Set A={1,2,3,4,5,6} two numbers from set A are selected at random without replacement and their sum recorded how many different
wolverine [178]
The minimum sum is 3 and the maximum is 11. So there are 9 different possible sums.
There are 30 ways to get these 9 different sums.
The table below shows all outcomes.

1 2 3 4 5 6
———————————-
1 | X 3 4 5 6 7
2 | 3 X 5 6 7 8
3 | 4 5 X 7 8 9
4 | 5 6 7 X 9 10
5 | 6 7 8 9 X 11
6 | 7 8 9 10 11 X
6 0
3 years ago
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