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coldgirl [10]
4 years ago
10

helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

ppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

Mathematics
2 answers:
scoray [572]4 years ago
8 0
The correct answer that you are looking for is C ( 75,000).
koban [17]4 years ago
6 0
The correct answer is A. 70,000. Because your looking at 4 to round up the seven but because 4 is lower than 5 it would just be 70,000
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Which of the following functions has the largest value when x = 3? c(x) = 3x2 + 5x + 22 j(x) = 12x a(x) = 9x
Olin [163]

To determine the function which has the largest value at x=3,

We will calculate the value of each function by substituting the value of x=3 in each of the given function.

Let us consider the first function,

c(x)=3x^{2}+5x+22

c(3)=3\times 3^{2}+5 \times 3+22

c(3)=27+15+22

c(3)=64

Let us consider the second function,

j(x)=12x

j(x)=12 \times 3 =36

Let us consider the third function,

a(x)=9x

a(x)=9 \times 3=27

Therefore, the function c(x) has the largest value at x=3.

3 0
3 years ago
Yesterday, the temperature at noon was 43.6 °F. By midnight, the temperature has decreased by 15.3 degrees. What was the tempera
ELEN [110]

Answer:

Temperature at midnight is -15.9 °F.

Step-by-step explanation:

Given: The temperature at noon was 43.6 °F. By midnight, the temperature has decreased by 15.3 degrees.

To find: The temperature at midnight.

Solution:

The temperature at noon was 43.6 °F.

Now, by midnight, temperature has decreased by 15.3 degrees.

So, first we need to convert the temperature in °F.

We know that, F=\frac{9}{5}C+32, where F is temperature in Fahrenheit and C is temperature in Celsius.

So, F=(\frac{9}{5} \times 15.3)+32  

\implies F=59.5

So, by midnight, temperature has decreased 59.5 °F

Therefore, temperature at midnight is 43.6-59.5=-15.9 °F

Hence, temperature at midnight is  -15.9 °F.

5 0
3 years ago
Emily measures the temperature of a bowl of water to be 9°C. Later she tells her friend that the water has become hot. What is t
viva [34]

Answer:

above 25°c

Step-by-step explanation:

Because thus is the room temperature so water will feel hot only when its above room temperature

3 0
3 years ago
Select the correct answer from the drop-down menu find the surface area of this triangular prism
11111nata11111 [884]
Would you please provide us with the options so we can help thanks
7 0
3 years ago
For randomly selected adults, IQ scores are normally distributed with a standard deviation of 15. The scores of 14 randomly sele
Inessa [10]
We would need the sample standard deviation for our hypothesis test.

STEP 1: Work out the mean of data set
μ = Sum of values in the set ÷ Number of values in the set
μ = 1686 ÷ 14
μ = 120.4 (rounded to one decimal place)

STEP 2: Subtract the mean from each value in the data set, and then square each answer. The table attached below shows the details of the calculation

STEP 3: Add the answers in STEP 2, then divide by 13.
Note: we divide by 13 instead of 14 because our data set is a sample set.

(∑x₁-μ)/13 = 1253.44÷13 = 96.42

The value obtained in STEP 3 is the variance. To obtain the standard deviation, we square root the variance
s = √96.42 = 9.819 (rounded to three decimal places)
----------------------------------------------------------------------------------------------------------------

We want to test the claim that the standard deviation of IQ scores of college students is less than 15. Putting this in the form of hypotheses we get:

H₀: σ=15
H₁: σ<15

The significance level, α, is 0.10

The degrees of freedom, v, is 14 - 1 = 13
Reading from the  Chi² table for α = 0.1 and degree of freedom = 13, we have the critical value ≥19.812 

The value of the test statistic is given as [(n-1)²s²] ÷ σ²
We have n = 14, s = 9.819, and σ = 15
test statistic = [(13)²(9.819)²] ÷ 15² = 72.417

72.417 is in the critical region (which is values ≥ 19.812) so the result is significant and H₀ is rejected. The standard deviation of IQ scores of college students is less than 15.

4 0
4 years ago
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