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SIZIF [17.4K]
3 years ago
11

Mr. Parker wants to rent a cargo van for a day. It will cost the daily fee of $50 plus $0.35 per mile driven. Let m = the number

of miles Mr. Parker drives for the day. Write an algebraic expression that shows the amount he will pay for the van. * 10 points \
Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0

Answer:

<h2>y=0.35m+50</h2>

Step-by-step explanation:

Step one:

given data

the daily fee= $50

cost per mile driven =$0.35

Let m = the number of miles

let y be the total cost

Step two

Required

the expression for the total cost is

An algebraic expression that shows the amount he will pay for the van. is  

<em>y=0.35m+50</em>

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ValentinkaMS [17]
First, you must understand the question. what % of 60 is 15, so I would write an equation to express this.

15 = 60x

From there, solve for x, so Divide by 60 on each side. The answer is 1/4, or 25%
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3 years ago
Please help me ! I will give you a heart and Brainly , if you put a link I will report you !
Triss [41]

Answer:

<4= 164

Step-by-step explanation:

the sum of any 2 angles of a triangle is equal to the exterior linear angle of the triangle

<1+<2=<4

8x+9+5x+12=14x+10

13x+21=14x+10

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2 years ago
A shopkeeper bought wheat for rs.35000. Due to leakage in the godown 1/7 of the total wheat was spoiled. He sold the good wheat
sladkih [1.3K]
<h2>Question: </h2>

A shopkeeper bought wheat for rs.35000. Due to leakage in the godown 1/7 of the total wheat was spoiled. He sold the good wheat at a gain of 10% and the spoiled when at a loss of 25%. Find his total gain or loss per cent.

Answer:

<h2>5%</h2>

<h2>step by step answer:</h2>

In the question we are given a shopkeeper or bought wheat for Rs. 35000. Now, due to leakage 17 of the total wheat is spoiled. Now, he sold the good wheat at 10% gain and the bad wheat at 25% loss. We need to find the total gain/loss percent.

According to the problem, the total cost of wheat is Rs. 35000.

Now, let us find the cost price of the spoiled wheat.

So, the cost of spoiled wheat is 17×Rs35000 which is equal to Rs. 5000.

Hence, the cost price of spoiled wheat is Rs 5000.

As we know that the spoiled wheat was sold at 25% loss, so we can say that if the cost price is considered as 100% so the selling price is considered as (100−25)% or 75%.

So, we got the selling price of spoiled wheat is 75100×5000=Rs3750

So, the cost price of spoiled wheat is Rs.5000 and selling price of spoiled wheat is Rs.3750.

Now, let us find the cost price of the good wheat.

Now, we will consider the good quality of wheat whose cost price is Rs(35000−5000) which is Rs. 30000.

Hence, the cost price is Rs. 30000.

As we know good quality wheat was sold at 10% gain so we can say that, if the cost price is 100% then the selling price will be (100+10)% or 110% .

Hence, the selling price of good quality wheat is 110100×Rs30000 which is Rs. 33000.

So, the cost price of good quality wheat is Rs. 30000 and selling price is Rs. 33000.

Let us find the total selling price of the wheat that the shopkeeper bought.

Now the total selling price of the wheat is Rs.3750+Rs.30000=Rs.36750.

Hence Profit = Total selling price − Total cost price

profit =Rs.36750−Rs.35000

=Rs.1750

profit %

=profitcost price×100%.

=175035000×100%.

=5%.

<h2>So, total profit is 5%.</h2>
6 0
3 years ago
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lisabon 2012 [21]

Answer:

sorry, i dont um, im setting, the acc, up and ,20

3 0
3 years ago
Please help.. 10 points
Leokris [45]

Answer:

z = 55.15432893

x = 59.61543424

y = 22.5166605

Step-by-step explanation:

To find length "z" you will have to use SOHCAHTOA.

Labelling the triangle will show us that the side marked "z" is the hyp and the side marked 39 is the opp.

sin 45 = \frac{39}{z}

z sin 45 = 39

         z  = \frac{39}{sin45}

         z = 55.15432893

Using Pythagoras' theorem, you can find that the adj = 39

In the other triangles POV, the adj is actually the opp.

Therefore, use tangent to find y.

tan 60 = \frac{39}{adj}

y tan 60 = 39

           y = \frac{39}{tan60}

           y = 22.5166605

Use Pythagoras's Theorem to find x.

23^{2} + 55^{2} = x^{2}\\\sqrt{23^{2} + 55^{2}}  = x\\59.61543424=x

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