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attashe74 [19]
3 years ago
14

25% of what number is 1.4

Mathematics
2 answers:
Yuki888 [10]3 years ago
7 0

Answer:

5.6

Step-by-step explanation:

erastovalidia [21]3 years ago
5 0

Answer:

  • the right answer is 0.35
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In algebra, symbols are used to represent numbers. Example: 5x=20 or 4x=24
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3 years ago
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Plz help me in this one
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Have you tried using photomath maybe you can find the answer on there.
8 0
3 years ago
124 7/8 gallons of water drained from a pool in 25 minutes how much water drained from pool each minute
boyakko [2]

first off, let's convert the mixed fraction to "improper", and then check,

\bf \stackrel{mixed}{124\frac{7}{8}}\implies \cfrac{124\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{999}{8}}\\\\ -------------------------------\\\\ \begin{array}{ccll} \stackrel{water}{gallons}&minutes\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \frac{999}{8}&25\\\\ x&1 \end{array}\implies \cfrac{\quad \frac{999}{8}\quad }{x}=\cfrac{25}{1}\implies \cfrac{\quad \frac{999}{8}\quad }{\frac{x}{1}}=25

\bf \cfrac{999}{8}\cdot \cfrac{1}{x}=25\implies \cfrac{999}{8x}=25\implies 999=200x \\\\\\ \cfrac{999}{200}=x\implies \stackrel{gallons}{4\frac{199}{200}}=x

4 0
4 years ago
A Pew Research Center report on gamers and gaming estimated that 49% of U.S. adults play video games on a computer, TV, game con
Veseljchak [2.6K]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have that:

  • 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.
  • 49% out of 2001 U.S. adults play video games, hence \pi = 0.49, n = 2001.

The lower bound of the interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 - 1.96\sqrt{\frac{0.49(0.51)}{2001}} = 0.4681

The upper bound of the interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 + 1.96\sqrt{\frac{0.49(0.51)}{2001}} = 0.5119

The 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.

To learn more about the z-distribution, you can take a look at brainly.com/question/25730047

5 0
3 years ago
Solve the linear equation. X + 5 = -2 ​
Vladimir79 [104]

Answer:

x=-7

Step-by-step explanation:

So we have the equation:

x+5=-2

To solve, subtract 5 from both sides. This is the subtraction property of equality:

(x+5)-5=(-2)-5

The left side cancels:

x=(-2)-5

Subtract on the right.

x=-7

So, our answer is -7.

7 0
3 years ago
Read 2 more answers
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