Answer:
3 strain would still alive after 48 hours
Step-by-step explanation:
Initial population of virus = 40000 grams
A certain virus is dying off at a rate of 18% per hour.
We are supposed to find how much of the strain would still be alive after 48 hours
Formula : 
=Initial population
N(t)= Population after t hours
r = rate of decrease = 18% = 0.18
t = time = 48 hours
So,the strain would still be alive after 48 hours=
Hence 3 strain would still alive after 48 hours
D) 47,000
0.60 (<em>x</em>+38,000)= 51,000
(0.60<em>x</em>)+22,800= 51,000
51,000-22,800= 28,200
28,200÷0.60= 47,000
0.06 (47,000+38,000)= 51,000
28,200+22,800= 51,000
Answer:
0.27
Step-by-step explanation:
You take 1.75, and subtract 1.48 from it. 1.75
<u>- 1.48</u>
0.27
It's not specified whether 1 is the 1st or 2nd roll: HOWER:
The 1st Roll is "1": P(odd sum/the 1st Roll is 1)
What is the sample space of all numbers starting with "1":
{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),} = 6
the couple of add sum=(1,2), (1,4), (1,6), =3
P(odd sum/ 1st is 1) = 3/6 =1/2
or in applying the formula:
P(odd sum/the 1st Roll is 1) =P(odd sum ∩ 1) / P(getting "1") it will give the same probability = 1/2
NOW if the 2nd Roll is "1", it 's still 1/2
