Question

The length of a rectangle is 3 more yrd than twice the width. The area is 869yrd^2

Answer 1

Width=20.108 yrd and Length=43.216 yrd

Step-by-step explanation:

Let width = w

Length =3+2w

Area = 869 yrd^2

We need to find length and width of rectangle.

The formula used is:

$Area= length*width$

Putting values:

$Area= length*width$

$869= (3+2w)*(w)$

$869= 3w+2w^2$

$2w^2+3w-869=0$

Using quadratic equation to find value of width w:

$w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a=2, b=3 and c=-869

$w=\frac{-3\pm\sqrt{(3)^2-4(2)(-869)}}{2(2)}$

$w=\frac{-3\pm\sqrt{6961}}{4}$

$w=\frac{-3\pm 83.4}{4}$

$w=\frac{-3+83.4}{4}\,\,and\,\,w=\frac{-3-83.4}{4}$

$w=20.108\,\,and\,\,w=-21.6$

Since width can't be negative so, width w=20.108

Length will be: L=3+2w = 3+2(20.108)=3+40.216=43.216

So, Width=20.108 yrd and Length=43.216 yrd

Keywords: Area of rectangle

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