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Vlad [161]
3 years ago
5

Click on the point that best represents the location of −√5 on the number line.

Mathematics
2 answers:
navik [9.2K]3 years ago
8 0

Answer:

The dot all the way on the left. The one between 2 and 3 I believe.

Step-by-step explanation:

musickatia [10]3 years ago
7 0

Answer:

The dot all the way to the left on the negative side.

Step-by-step explanation:

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Write 1.67% as a decimal. thx :)
Bas_tet [7]

Answer:

0.0167

Step-by-step explanation:

divide by 100

6 0
3 years ago
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Find the value of x. Round to the nearest tenth.
elena55 [62]

Using tan(x) = 4/3

X = arctan(4/3)

X = 53.1 degrees

4 0
3 years ago
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2x + 6 = x – 1<br> Real solutions
pogonyaev

Answer:

x = -7

Step-by-step explanation:

2x+6 = x-1

add -6 to both sides

2x = x-7

add -x to both sides

x = -7

6 0
3 years ago
What is the range for this data set?<br> 22, 7, 14, 13, 38, 12, 19, <br> 17, 49, 13, 9, 18, 36​
Degger [83]

Answer:

from 7 to 49 or (7, 49)

Step-by-step explanation:

Range means the limit of the data set. Basically, the low part of the range is the lowest number in the set and the high part of range is the highest part.

5 0
3 years ago
A​ chef's specialty calls for ​one- fiftieth of an ounce of a spice per serving. The chef has a digital scale that shows the wei
Anna35 [415]

Answer:

The scale reading that the chef need to see for this spice when preparing the specialty for 43 people is 0.86.

Step-by-step explanation:

In order to find the answer, you need to multiply the amount that the chef uses per serving for the number of servings. The statement indicates that the chef uses ​one- fiftieth of an ounce of a spice per serving and this is represented as 1/50 and you have to multiply this for 43 that is the number of people.

You can find 1/50 as a decimal dividing 1 by 50:

1/50=0.02

Now, you can multiply this value for 43:

0.02=43=0.86

According to this, the answer is that the scale reading that the chef need to see for this spice when preparing the specialty for 43 people is 0.86.

3 0
3 years ago
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