The length of the unknown sides of the triangles are as follows:
CD = 10√2
AC = 10√2
BC = 10
AB = 10
<h3>Triangle ACD</h3>
ΔACD is a right angle triangle. Therefore, Pythagoras theorem can be used to find the sides of the triangle.
where
c = hypotenuse side = AD = 20
a and b are the other 2 legs
lets use trigonometric ratio to find CD,
cos 45 = adjacent / hypotenuse
cos 45 = CD / 20
CD = 1 / √2 × 20
CD = 20 / √2 = 20√2 / 2 = 10√2
20² - (10√2)² = AC²
400 - 100(2) = AC²
AC² = 200
AC = √200 = 10√2
<h3>
Triangle ABC</h3>
ΔABC is a right angle triangle too. Therefore,
Using trigonometric ratio,
cos 45 = BC / 10√2
BC = 10√2 × cos 45
BC = 10√2 × 1 / √2
BC = 10√2 / √2 = 10
(10√2)² - 10² = AB²
200 - 100 = AB²
AB² = 100
AB = 10
learn more on triangles here: brainly.com/question/24304623?referrer=searchResults
Product <em /><em /><em>is the answer to a multiplication problem.
Multiple is the product of the number and whole numbers.
Hopefully this helps! :D :D
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Answer:
The graph below shows the answer to
2x - 3y < 12
Also shown as
-3y < -2x + 12
Step-by-step explanation:
You can rearrange the inequality by subtracting 2x from both sides to isolate the y.
You now have -3y < 12 -2x
which can be put into the standard linear equation form of
-3y < -2x + 12
Then you divide both sides by -3 to get singular value of y, which is something like
-3/-3y < -2/-3x + 12/-3
which is
y > 2/3x -4
Note: I switched direction of the inequality because you are dividing both sides by a negative value.
Answer:
1.) 2x-y=-7 --> y=2x + 7
2.) 5x+3y=12 --> y= -5/3x + 4
3.) x-y=1 --> y= x- 1
4.) x-3y=-15 --> y=1/3x + 5
5.) 8x-10y=20 --> y=4/5x - 2
6.) 14x+6y=36 --> y=-7/3x+6
Step-by-step explanation:
Hope this helped.
B but I'm not as sure though
