Answer:
Hi I'm learning the same thing and I just got it I think it's C=43.98cm
Answer:
the correct answer is 0.84
give brainliest plzzz
The answer is C. 3, because you're essentially saying 9 - (3 × 2) and that is 9 - 6, which equals 3. I hope this helps!
Answer:
False
Step-by-step explanation:
To find <A, we can do 5x - 80 = 3x + 20.
As we simplify, we will get 2x = 100, which is x = 50
Therefore, <A will be 50 degrees and not 45 degrees.
Also, if you need y, you can do:
3y - 7 = y + 7
2y = 14
y = 7
Answer:

Step-by-step explanation:
<u><em>The options of the question are</em></u>
2(x − 1)2 = 4
2(x − 1)2 = −4
2(x − 2)2 = 4
2(x − 2)2 = −4
we have

This is a vertical parabola open upward
The vertex represent the minimum value
The quadratic equation in vertex form is

where
a is a coefficient
(h,k) is the vertex
so
Convert the quadratic equation in vertex form
Factor 2 leading coefficient

Complete the squares


Rewrite as perfect squares

The vertex is the point (1,-4)
Move the constant to the right side
