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Usimov [2.4K]
3 years ago
9

PLEASE ITS DUE TODAY. Which expression has a conffcient of 7?

Mathematics
2 answers:
gregori [183]3 years ago
7 0

Answer:

the first one

Step-by-step explanation:

because x has an coefficient

DENIUS [597]3 years ago
3 0

Answer: The answer is C

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Solve for x 0.3·0.2+0.3÷0.2=x
RoseWind [281]

Answer:

x equals 2

Step-by-step explanation:

.3-.2+.3 is .4

.4 divided by .2 is 2

then you are left with 2 = x

4 0
2 years ago
Use summation notation to write the series 49 + 54 + 59 +... for 14 terms.
My name is Ann [436]

Answer:

Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.

it is given by:  a_n = a+(n-1)d where a is the first term , n is the number of term and d is the common difference.

Given the series: 49 + 54 + 59+ ......

here, Common difference(d) = 5

First term(a) = 49

by definition we have;

For nth term

a_n = a+(n-1)d

a_n = 49+(n-1)5

a_n =49+5n -5 = 5n + 44

To write the series using summation notation for 14 terms

Summation symbol '\sum'

The series for 14th terms is given by;

\sum_{n=1}^{14}(5n +44)


5 0
3 years ago
Read 2 more answers
-5/8 ÷ 9/10<br><br> A. -25/36<br><br> B. -9/16<br><br> C. -45/80<br><br> D. -1/36
Oduvanchick [21]

A. -25/36

If There Is Any Other Fraction problems That You Need Help With, Go To This Site http://www.calculatorsoup.com/calculators/math/fractions.php

5 0
2 years ago
Read 2 more answers
The probability that a civil servant own a car is 1/6,if two civil servants are selected at random.find the probability that
Elodia [21]

Answer:

The data we have is:

the probability that a civil servant own a car is 1/6

Two civil servants are selected at random.

a) The probability that each own a car.

Ok, here we have two events:

Person 1 haves a car.

Person 2 haves a car.

The probability of each of those events is the same, 1/6.

P1 = 1/6

P2 = 1/6

Now, the probability of both events happening at the same time is equal to the product of the individual probabilities.

P = P1*P2 = (1/6)*(1/6) = 1/36.

b) Only one has a car.

Suppose that Person 1 has the car and Person 2 has not a car.

The probability for person 1 is 1/6.

And for person 2, is the negation of having a car:

So if we have prob of having a car = 1/6

Then the probability of not having a car is = 1 - 1/6 = 5/6.

Then we have:

P1 = 1/6

P2 = 5/6.

The joint probability is:

P = P1*P2 = (1/6)*(5/6) = 5/36.

But we also have the case where person 1 does not have a car, and person 2 does have one, then we have a permutation, and the actual probability is two times the obtained above.

P = 2*(5/36) = 10/36

4 0
3 years ago
PLZ HELP IF UR 100% SURE !!!
WARRIOR [948]
The answer is d ok dine
7 0
3 years ago
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