What is the center of the circle (x+7)^2+(y+4)^2=25
1 answer:
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Answer:
(-7, -4)
Step-by-step explanation:
Compare the given equation to the standard form equation for a circle with center (h, k) and radius r.
(x -h)^2 +(y -k)^2 = r^2
You see that ...
-h = +7 ⇒ h = -7
-k = +4 ⇒ k = -4
Then the center is ...
(h, k) = (-7, -4)
__
The radius is ...
r^2 = 25 ⇒ r = √25 = 5 . . . radius of the circle
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