Answer:
0≤y≤5
Step-by-step explanation:
The range is the values of the output, or in this case the y values
The y values go from 0 to 5
0≤y≤5
(8/9)^2 is just 8/9 squared, or 8/9 * 8/9. This is 64/81, and cannot be reduced. This is therefore our answer.
The answer to number 13 questions is 1198
Answer: 233 min
Step-by-step explanation:
This problem can be solved by the following equation:
(1)
Where:
is the quantity left after time 
is the initial quantity
is the time elapsed
is the constant of decay for the material
So, firstly we need to find the value of from (1) in order to move to the next part of the problem:
(2)
Applying natural logarithm on both sides of the equation:
(3)
(4)
(5)
(6)
(7) Now that we have the value of we can solve the other part of this problem: Find the time for 
.
In this case we need to isolate from (1):
(8)
(9)
Finally:
The answer would be C b/c negative 2 times 11 is positive 22 and 2negatives equal a positive and then negative 5 times 4 equal 20 it would be 22/20 divide be top and bottom by 2 and you get your answer .
