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2 years ago

8

The perimeter is 36.what dose x have to be

1 answer:

KIM [24]2 years ago

3 0

The answer would be 4

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Perform the indicated computation. Write the answer in scientific notation. 12x10^4\3x10^−2

Paul [167]

Let us consider the given expression:

$\frac{12 \times 10^{4}}{3 \times 10^{-2}}$ in the scientific notation.

= $\frac{12 \times 10^{4} \times 10^{2}}{3 }$

[Using the law of exponents, which states

$a^{m} \times a^{n} = a^{m+n}$ ]

= $\frac{12 \times 10^{6}}{3}$

On dividing, we get

= $4 \times 10^{6}$

Hence, it is the required scientific notation of the given expression.

6 0

2 years ago

Please help ill mark brainliest

liraira [26]

Answer:

it's 11

Step-by-step explanation:

8 0

2 years ago

Describe the number and type of roots for the polynomial. (how many real and complex?)

DENIUS [597]

This is a cubic equation so it will have a total of three roots.
there is only one change of sign so the equation will have one positive real root.
The other 2 roots will be negative and might be real or complex

7 0

2 years ago

D/d{cosec^-1(1+x²/2x)} is equal to

SIZIF [17.4K]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

Let assume that

$\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

We know,

$\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}$

So, using this, we get

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)$

Now, we use Method of Substitution, So we substitute

$\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}$

So, above expression can be rewritten as

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)$

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)$

$\rm\implies \:y = 2z$

$\bf\implies \:y = 2 {tan}^{ - 1}x$

So,

$\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x$

Thus,

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

$\rm \: = \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)$

$\rm \: = \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)$

$\rm \: = \: 2 \times \dfrac{1}{1 + {x}^{2} }$

$\rm \: = \: \dfrac{2}{1 + {x}^{2} }$

<u>Hence, </u>

$\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}$

<u>Hence, Option (d) is </u><u>correct.</u>

6 0

1 year ago

In 2000, the cost of tuition at a UC school was $3200. The tuition has increased by about 8% every year. How much can you expect

miss Akunina [59]

Answer:

$51, 200

Step-by-step explanation:

First is to find the increase of tuition

$3,200 × .8 = $2560

then subtract the year.

2020-2000=20

lastly multiply the year and the increase of tuition to know the final answer

$2560 × 20 = $51,200

3 0

2 years ago