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Alex_Xolod [135]

3 years ago

14

Brian rides a bicycle at a rate of 12 meters per second. Let m represent the number of meters biked and s the number of seconds.

Which student modeled the situation correctly? June’s work 12m = s Mina’s work 12s = m Chen’s work m = 12 + s David’s work m = 12 – s

2 answers:

KatRina [158]3 years ago

8 0

Answer:

Step-by-step explanation:

Mina's Work is the correct answer!

harina [27]3 years ago

8 0

Answer:

Mina's Work

Step-by-step explanation:

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Graph the function y = |1.6x – 2| – 3.2. Over which interval is the function increasing?

klasskru [66]

You are to graph <span>y = |1.6x – 2| – 3.2. I trust you know that the graph of y=|x| is v-shaped, opening up, with vertex at (0,0).

Let's rewrite </span><span>y = |1.6x – 2| – 3.2 by factoring 1.6 out of |1.6x - 2|:

</span><span>y = 1.6*|x – 2/1.6| – 3.2

This tells us that the vertex of </span><span>y = |1.6x – 2| – 3.2 is at (2/1.6, -3.2). If you need an explanation of why this is, please ask.

Plot the vertex at (1.25, -3.2).
Find the y-intercept: Let x = 0 in </span><span>y = |1.6x – 2| – 3.2 and find y:

y = 2-3.2 = -1.2

The y-intercept is located at 0, -1.2)

Plot this y-intercept.

Now draw a straight line from the vertex to this y-intercept. Reflect that line across the y-axis to obtain the other half of the graph.</span>

8 0

3 years ago

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George's bank balance last month was) -£350

kvasek [131]

Answer:

mark me as brainliest please

1112

Step-by-step explanation:

1550-350=1200

1200-88=1112

4 0

3 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

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Vesna [10]

63 years :) Hope this helps ;D

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4vir4ik [10]

Answer:

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Step-by-step explanation:

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