Which of the the following is equivalent to 2 to the negative 3rd power? 1.-6 2.1/6 3.-8 4.1/8

Identify the exponent in the following number: 2^5 A. 2 B. 5 C. 16 D. 32

Sophie [7]

Answer: 5

Explanation: This type of algebraic expression is called a power.

Here, 2 represents the base and the represents the exponent.

4 0

3 years ago

Factor the expression 12x^2 +7x+1

Leona [35]

Answer:

$\boxed{\textsf{ The factorised form is \textbf{(4x+1)(3x+1)}.}}$

Step-by-step explanation:

A quadratic polynomial is given to us and we need to find its factorised form . The given quadratic polynomial is ,

$\sf\implies p(x)= 12x^2+7x+1$

And this equation is similar to the equation in ax² + bx + c form . So in order to factorise it .

Step 1: Multiply the coefficient of x² with the constant term .

Here the coefficient of x² is 12 and the constant term is 1 . So on multiplying them we get 12*1= 12 .

Step 2: Look out for the possible factors of the number .

Here the obtained number is 12 . So the possible factors of 12 is

1 *12
-1*-12
2*6
-2*-6
4*3
-4*-3

Step3: Choose the factor whose sum is equal to the coefficient of the middle term .

Here we can see that the middle term is 7 . And the sum of 4 and 3 is equal to 7 . Hence here we will break 7x as 4x + 3x .

Step 4: After proper arrangements take out the common term and then factorise.

After suitable rearrangment we get ,

$\sf\implies p(x)= 12x^2+4x+3x+1 \\\\\sf\implies p(x)= 4x(3x+1)+1(3x+1) \\\\\implies\boxed{\red{\sf p(x)= (4x+1)(3x+1)}}$

7 0

3 years ago

HELPPPPPPPPPP Add & subtract matrices ..... PLZ GIVE THE ANSWER .. THANKSSSSS .

ale4655 [162]

Answer:

$\left[\begin{array}{cc}0&-1\\-1&0\\-1&-1\end{array}\right]$

Step-by-step explanation:

In this question we have to subtract the corresponding entries of column of matrix 1 and the matrix 2 corresponding entries

$=\left[\begin{array}{cc}-1&0\\1&-2\\1&3\end{array}\right]-\left[\begin{array}{cc}-1&1\\2&-2\\2&4\end{array}\right] \\=\left[\begin{array}{cc}-1-(-1)&0-1\\1-2&-2-(-2)\\1-2&3-4\end{array}\right]\\=\left[\begin{array}{cc}-1+1&-1\\-1&-2+2\\-1&-1\end{array}\right]\\=\left[\begin{array}{cc}0&-1\\-1&0\\-1&-1\end{array}\right]$

8 0

3 years ago

I need help please ?!!!!!

allsm [11]

Answer:

-6x² - x + 35

The answer is The Last One

Step-by-step explanation:

Hope This Helps :)

Plz Mark Brainliest!!!

5 0

3 years ago

8.

iren2701 [21]

Are these the actual figures?

8 0

3 years ago