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poizon [28]
3 years ago
5

Solve the inequality, & show step by step |x+1|>5

Mathematics
1 answer:
pantera1 [17]3 years ago
5 0

Step-by-step explanation:

Here you go i think its good

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Hello there,


22,119 to the nearest hundred would be 22,100 because 119 is closer to the hundred and not 200.

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~Jurgen
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Out of the 1236 employees who work for a particular company, 748 of them work in an office. One employee is selected every month
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4 years ago
The combined area of two squares is 80 square centimeters. Each side of one square is twice as long as a side of the other squar
olganol [36]

Answer:

The length of each side of the larger square is<u> 8 </u>centimeter.

Step-by-step explanation:

Given:

The combined area of two squares is 80 square centimeters. Each side of one square is twice as long as a side of the other square.

Now, to find the length of each side of the larger square.

Let s be the length of the smaller square.

So, the length of the larger square = 2s.

Now, we find the areas of the square by putting formula:

The area of smaller square = length²  =s^2.

The area of larger square = (length)²  =(2s)^2=4s^2.

As, given:

The combined area of two squares is 80 square centimeters.

According to question:

s^2+4s^2=80\\5s^2=80

<em>So, dividing both sides by 5 we get:</em>

s^2=16

<em>Using square root on both sides we get:</em>

s=4\ centimeter.

And, to get the  length of each side of the larger square we substitute the value of s:

2s=2\times 4=8\ centimeter.

<u>The length of larger square = 8 centimeter</u>

Therefore, the length of each side of the larger square is 8 centimeter.

8 0
3 years ago
If f(x)=2x^2-5and g(h)=3x+3 find f-g (x)
sammy [17]

(f-g)(x)=f(x)-g(x)\\\\\text{We have}\ f(x)=2x^2-5\ \text{and}\ g(x)=3x+3.\ \text{Substitute:}\\\\(f-g)(x)=(2x^2-5)-(3x+3)=2x^2-5-3x-3=2x^2-3x-8\\\\Answer:\ \boxed{(f-g)(x)=2x^2-3x-8}

7 0
3 years ago
Jake is traveling 14 mph in his boat. After 5 hours, how far will he have traveled?
Luden [163]

Answer: 70

Step-by-step explanation: 14 times 5 = 70

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3 years ago
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