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3 years ago

I’ll give u brainiest pls help me im so lost

Mathematics

1 answer:

Vlad1618 [11]3 years ago

3 0

Answer:

(f o g)(4)=27

Step-by-step explanation:

(f o g)(4)=2x+5

f(g(4))=2x+5

f(4²-2(4)+3)=2x+5

f(16-8+3)=2x+5

f(8+3)=2x+5

f(11)=2x+5

f(11)=2(11)+5

f(11)=22+5

f(11)=27

Therefore, (f o g)(4)=27

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Determine the solution set of each equation

maks197457 [2]

A=x1 = -8,x2 =2, B=x1= -5,x2=5, C=y1 = -4, y2 =5, D=y 18 over 5

alternative form

y=3 3over 5, =3.6

And E=x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667.

question A

Solving steps:Solve the quadratic equation

x²+6x-16=0

write 6x as a difference

x2 +8x-2x-16=0

factor out x for the expression

xx(x+8)-2x-16=0

factor out -2 from the expression

xx(x+8)- 2(x+8)=0

factor out x+8 from the expression

(x+8)x(x- 2)=0

when the product of factors equals 0,at least one factor is 0

x+8=0

x - 2=0

solve the equation for x

x= -8

x - 2=0

solve the equation for x

x= -8

x =2

the equation has 2 solution

x1 = -8,X2 =2

answer is

x1 = -8,x2 =2

Solving steps:Number of solution

x²+6x-16=0

Determine the number of solution using the

discriminant D =b²- 4ac

D =6²- 4x1x(-16)

simply the expression

D=100

Since D>0, the quadratic equation has 2 real solution

2 real solution

Answer is

2 real solution

Question B

Solving steps:Solve the quadratic equation

x²-25=0

Move the constant to the right-hand side and change its sign

x²=25

Take the square root of both sides of the equation and remember to use both positive and negative roots

x=+5

Write the solutions,one with a +sign and one with a -sign

x= -5

x=5

The equation has 2 solutions

x1= -5,x2=5

the answer is

x1= -5,x2=5

Solving steps:Number of solution

x²-25=0

Determine the number of solutions using the discriminant D=b²- 4ac

D=0²- 4x1x(-25)

Simply the expression

D=100

Since D>0,the quadratic equation has 2real solutions

Answer is

2real solutions

answer of question C is

y1 = -4, y2 =5

Answer of question D is

y 18 over 5

alternative form

y=3 3over 5, =3.6

Answer of question E is

x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667

Please mark as brainiest

3 0

4 years ago

Read 2 more answers

During an election, Albert received 60% of the 30 votes cast. Anthony received the remaining votes. How many more votes did Albe

r-ruslan [8.4K]

Answer:

6 votes!

Step-by-step explanation:

Albert: 60% of 30= 18

Anthony: 40% of 30= 12

18 - 12= 6

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3 years ago

I'll Mark you brainliest!! I will report answers if you answer for points. Period.

skad [1K]

Step-by-step explanation:

SAS is Side - Angle (between the sides) - Side

BC and CD are shown to be congruent with the markers that cross the line segments.

AC and AC are the same because they are the same.

The only things needed are the congruent angles between the sides.

The angles are ACD and ACB, because those are the angles between AC and BC and AC and CD.

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3 years ago

PLEASSSEEE HELPPP ASAPPPPP

Ipatiy [6.2K]

Answer:

first one is 32

the second one is 53

Step-by-step explanation:

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3 years ago

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There are 3 red marbles, 5 green marbles, and 2 blue marbles in a jar. Event A is defined as drawing a red marble from the jar o

Anastaziya [24]

P(B/A) is $\frac{5}{9}$ in the simplest form

Step-by-step explanation:

Let us explain how to solve the problem

P(B|A) is called the "Conditional Probability" of B given A
Conditional probability is the probability of one event occurring with some relationship to one or more other events that means event A has already happened, now what is the chance of event B
The formula for conditional probability is P(B|A) = P(A and B)/P(A), where P(A and B) is P(A) . P(B given A occurred)

∵ There are 3 red marbles, 5 green marbles, and 2 blue

marbles in the jar

∴ The total number of the marbles in the jar = 3 + 5 + 2 = 10

∵ Two marbles are drawn from the bag, one after the other without

replacement

- That means red is already occurred when green is happened,

so it is a "Conditional Probability" of green given red

P(B/A) = P(A and B)/P(A)

∵ Event A is defined as drawing a red marble from the jar on

the first draw

∴ P(A) = P(red)

∵ P(red) = $\frac{3}{10}$

∴ P(A) = $\frac{3}{10}$

∵ Event B is defined as drawing a green marble on the second draw

∴ P(B) = P(green)

- The number of marbles after the red is chosen is 9

∵ P(green) = $\frac{5}{9}$

∴ P(B) = $\frac{5}{9}$

- Find P( A and B)

∴ P(A and B) = ( $\frac{3}{10}$ ) . ( $\frac{5}{9}$ )

∴ P(A and B) = $\frac{15}{90}$

- Simplify the fraction by divide up and down by 15

∴ P(A and B) = $\frac{1}{6}$

∵ P(B|A) = P(A and B)/P(A)

- Substitute the values of P(A and B) and P(A) in the rule above

∴ P(B/A) = $\frac{\frac{1}{6}}{\frac{3}{10}}$

- Simplify the fraction

∵ $\frac{1}{6}$ ÷ $\frac{3}{10}$ = $\frac{1}{6}$ × $\frac{10}{3}$ = $\frac{10}{18}$

- Divide up and down by 2

∴ P(B/A) = $\frac{5}{9}$

P(B/A) is $\frac{5}{9}$ in the simplest form

Learn more:

You can learn more about probability in brainly.com/question/10744457

#LearnwithBrainly

7 0

3 years ago

Read 2 more answers