Answer:

Step-by-step explanation:
Answer:
40951
Step-by-step explanation:
Using the principles of inclusion - Exclusion
Where C(n,r)=n!/(n-r)!r!
Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000
Total Number of elements in each pair including number repetition of sets is given as
=(1000) × C(5, 2) =10000
Number of elements in each triple of sets is given as
=(100) × C(5, 3) =1000
Number of elements in every four sets
=(10) × C(5, 4)=50
Number of elements in every one set
(1) × C(5, 5)=1
Therefore total number of unique elements=50000-10000+1000-50+1
=40951
Whats the question for this question
Great question!
If you draw a calendar see attachment for mine.you will see that the dates for Basketball are
3,6,9,12,15,18,21,24,27,30
and the dates for Babysitting are
7,14,21,28
There would only be a conflict on the 21st! So the answer is 1 time!
LABC is a 30°angle point B is at (3,2)