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san4es73 [151]
3 years ago
6

using the standard form ax^2+bx+c=0 of the given quadratic equation, factor the left hand side of the equation into two linear f

actors. ​
Mathematics
1 answer:
Galina-37 [17]3 years ago
5 0

Answer:

See below

Step-by-step explanation:

Since you didn't give an actual quadratic equation and just the standard form equation, I will reduce ax^2+bx+c=0:

(ax+p)(x+q) where p+q=b and pq=c

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If $560 is sheared in the ratio 2:3:9 , the difference between the largest and the smallest shares is
Lesechka [4]

Answer:

The difference between the largest and the smallest shares is $280

Step-by-step explanation:

Total amount to be shared = $560

Ratios of share are 2:3:9 => Total of 14 equal portions

To get one portion, $560 / 14 = $40

First share is 2, therefore $40 x 2 =        $80 (smallest share)

Second share is 3, therefore $40 x 3 = $120

Third share is 9, therefore $40 x 9 =    $360 (largest share)

                                            <u>TOTAL =     $560</u>

The difference between the largest and the smallest = $360 - $80

                                                                                        = $280

7 0
3 years ago
In 3 billion repetitions of an experiment, a random event occurred in 500 million cases.
Eddi Din [679]
5/6 is your other percentage
5 0
3 years ago
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I need help with 4a and 4b
Bas_tet [7]

Complementary angels are two angles that equal 90 when added so S degrees + Z degree = 90 degrees or 50 degree + 40 degree = 90 so forth 4B in comments

6 0
3 years ago
(x+6) is a factor of f(x). Solve f(x)=0.<br>x3 - 52x – 96​
Mars2501 [29]
<h3>I'll teach you how to solve f(x)=0x63 - 52x – 96​</h3>

----------------------------------------------------------

f(x)=0x^3 - 52x – 96​

Apply rule:

0 * a= 0

0-52x-96

Group like terms:

-52x+0-96

Add/subtract the numbers:

0-96= -96

-52x-96

Your Answer Is -52x-96

plz mark me as brianliest if this helped :)

6 0
3 years ago
What is (3xy^2)(-6xy^4)
krok68 [10]

Answer:

-18x^2y^6

Step-by-step explanation:

we have

(3xy^2)(-6xy^4)

Applying property of exponents

x^{m} x^{n}=x^{m+n}

(3xy^2)(-6xy^4)=(3)(-6)(x^{1+1})(y^{2+4})=(-18)(x^{2})(y^{6})=-18x^2y^6

5 0
3 years ago
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