Sorry I don't see a picture. But...
If they add up to 90 degrees, they are complimentary
If they add up to 180 degrees ( a straight line) they are supplementary.
If they are vertical, they will be on either side, like two v's ><
Answer: Answer Number 1; Line AB is similar to
line EF
Line BC is similar to line FG
Line CD is similar to line GH
Line DA is similar to line HE
Step-by-step explanation: First and foremost both
quadrilaterals are similar but of varying dimensions.
If we label both trapezoids as ABCD and EFGH
respectively, then it follows that the corresponding
lines (as stated in the answer above) would also be
similar.
Same applies to the four angles in the interior of the
trapezoids.
Number 2, Angle A equals Angle E
Angle B equals Angle F
Angle C equals Angle G
Angle D equals Angle H
Number 3,
If the scale factor between both figures is 2:3, then
for every length of a side in figure ABCD, the
corresponding side in figure EFGH would be
multiplied by 3/2.
Therefore if AD is 8cm, then EH equals 8 x 3/2
That gives us 12cm.
If GH is 6cm, then DC equals 6 x 2/3. That gives
us 4cm.
If AB is 3 times the length of DC, then AB equals 3
x 4, that gives us 12cm.
If AB is 12cm, then EF equals 12 x 3/2. That gives
us 18cm.
Take note that the shapes are both isosceles
trapezoids, o we have two sides of equal length, AD
and BC in the first figure and then EH and FG in the
other figure.
The first trapezoid has sides 8cm, 12cm, 8cm and
4cm. The perimeter is given as 8+12+8+4 32cm.
The second trapezoid has sides 12cm, 18cm, 12cm
and 6cm. The perimeter is given as 12+18+12+6=
48cm.
Cara has $25 to buy dry pet food and treats.
If she buys 9 pounds of dog food and a pound of dog food costs $2, you can calculate how many treats she can buy using the following steps:
9 pounds of dog food * $2 = $18
$25 - $18 = $7 left
$7 / $1 = 7 treats
Result: Cara can buy 7 treats.
Answer:
13/3, 4.4, 
, 19/4
Step-by-step explanation:
Answer:
A) Non-collinear- does not lies on straight line
B) Collinear- lie on straight line
Step-by-step explanation:
We have to check collinearity of three points.
The points 
are said to be collinear if,
![\left[\begin{array}{ccc}x_1&y_1&z_1\\x_2&y_2&z_2\\x_3&y_3&z_3\end{array}\right] = 0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx_1%26y_1%26z_1%5C%5Cx_2%26y_2%26z_2%5C%5Cx_3%26y_3%26z_3%5Cend%7Barray%7D%5Cright%5D%20%3D%200)
A) A(2, 5, 3), B(3, 7, 1), C(1, 4, 4)
![\left[\begin{array}{ccc}2&5&3\\3&7&1\\1&4&4\end{array}\right] \\\\=2(28-4)-5(12-1)+3(12-7)\\= 8 \neq 0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%265%263%5C%5C3%267%261%5C%5C1%264%264%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%3D2%2828-4%29-5%2812-1%29%2B3%2812-7%29%5C%5C%3D%208%20%5Cneq%200)
Thus, the given points are not collinear.
B) D(0,-5,5), E(1,-2,4), F(3,4,2)
![\left[\begin{array}{ccc}0&-5&5\\1&-2&4\\3&4&2\end{array}\right] \\\\=0(-4-16)+5(2-12)+5(4+6)\\=0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-5%265%5C%5C1%26-2%264%5C%5C3%264%262%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%3D0%28-4-16%29%2B5%282-12%29%2B5%284%2B6%29%5C%5C%3D0)
Thus, the given points are collinear.
