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dolphi86 [110]
3 years ago
9

The diameter of a circle is 3 cm. Find the circumference to the nearest tenth.

Mathematics
1 answer:
nika2105 [10]3 years ago
8 0

Answer:

The answer is 9.4 cm.

Step-by-step explanation:

To solve for the circumference of the circle, use the circumference formula, which is C = 2 \pi r.

Next, in the problem, the circle has a diameter measure but no radius measure. To find the radius of this circle, divide the diameter (3 cm) by 2, and it will equal 1.5 cm. The radius is being divided by 2 because the radius of any circle is equal to half the diameter of the circle.  

Then, plug in the information given from the problem into the formula, and the formula will look like C = (2) (\pi) (1.5 cm).

Finally, solve the equation, and the answer is 9.4 cm.  

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3x+4y=24 ,4x+3y=22 simultaneous equations simultaneous equ
Vinvika [58]

Answer:

x=64

y=54

Step-by-step explanation:

3x+4y=24 4(24-4y\3)+3y=22

x=24-4y/3 96-12y\3+3y=22

x=24-4(54)/3

x=-64 96/3-22=3y/3

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2 years ago
The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re
Zolol [24]

Answer:

a) df=n-1=16-1=15

The statistic calculated is given by t=3.3  

Since is a one-side upper test the p value would be:      

p_v =P(t_{15}>3.3)=0.0024  

So since the p value is lower than the significance level pv we reject the null hypothesis.

b) df=n-1=8-1=7

The statistic calculated is given by t=1.8  

Since is a one-side upper test the p value would be:      

p_v =P(t_{7}>1.8)=0.057  

So since the p value is higher than the significance level pv>\alpha we FAIL to reject the null hypothesis.

c) df=n-1=26-1=25

The statistic calculated is given by t=-0.6  

Since is a one-side upper test the p value would be:      

p_v =P(t_{25}>-0.6)=0.723  

So since the p value is higher than the significance level pv>\alpha we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation      

\bar X represent the sample mean

s represent the standard deviation for the sample

n sample size      

\mu_o =20 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:      

Null hypothesis:\mu \leq 20      

Alternative hypothesis:\mu > 20      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:  

df=n-1=16-1=15

The statistic calculated is given by t=3.3  

Since is a one-side upper test the p value would be:      

p_v =P(t_{15}>3.3)=0.0024  

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(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:  

df=n-1=8-1=7

The statistic calculated is given by t=1.8  

Since is a one-side upper test the p value would be:      

p_v =P(t_{7}>1.8)=0.057  

So since the p value is higher than the significance level pv>\alpha we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

 First we need to calculate the degrees of freedom given by:  

df=n-1=26-1=25

The statistic calculated is given by t=-0.6  

Since is a one-side upper test the p value would be:      

p_v =P(t_{25}>-0.6)=0.723  

So since the p value is higher than the significance level pv>\alpha we FAIL to reject the null hypothesis.

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