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2 years ago

1)4-2(x + 19) = 50 2)7(x-3)-14=70

Mathematics

2 answers:

zalisa [80]2 years ago

8 0

2x+38=50
2x+38-38=50 -38
2x =12
2x/2 =12/2
x=6

mojhsa [17]2 years ago

7 0

Answer:

1. x=4

2. x=15

Step-by-step explanation:

1. Add '-42' to each side of the equation.

42 + -42 + -2x = 50 + -42

Combine like terms: 42 + -42 = 0

0 + -2x = 50 + -42

-2x = 50 + -42

Combine like terms: 50 + -42 = 8

-2x = 8

Divide each side by '-2'.

x = -4

Simplifying

x = -4

Add '35' to each side of the equation.

-35 + 35 + 7x = 70 + 35

Combine like terms: -35 + 35 = 0

0 + 7x = 70 + 35

7x = 70 + 35

Combine like terms: 70 + 35 = 105

7x = 105

Divide each side by '7'.

x = 15

Simplifying

x = 15

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ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

Subtract 7 from both sides of the equation.

$${x+7-7}=0-7$

x = –7

The value of x is –7.

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Answer:

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Step-by-step explanation:

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