Answer:
1.5 grams of protein.
Step-by-step explanation:
The equation that represents the relationship between protein and fat is as follows :
4p + 9f = 60 ....(1)
We need to find the grams of protein are there if there are 6 grams of fat in the snack.
Put f = 6 in the above equation (1).
4p + 9(6)= 60
4p + 54 = 60
Subtract 54 to the both sides,
4p + 54-54 = 60-54
4p = 6
⇒ p = 1.5 grams
It means the snack contains 1.5 grams of protein.
AC = 8.9
BC = 6.5
(90% angle)
8.9 x 6.5 = <span>57.85
57.85/2 = 28.925
Area of ^ABC = 28.925 cm squared
DE = 55.1
55.1/ 11.02 = 5
DEF is 5 times as big as ABC
DF = 44.5
FE = 32.5
44.5 x 32.5 = 1446.25
1446.25/2 = 723.125
I am not positive but I believe DEF = 723.125 cm squared
Good Luck on the Test!! :D
</span>
Answer:
50
Step-by-step explanation:
Answer:
a. Practically speaking, you compute the differential in much the same way you compute a derivative via implicit differentiation, but you omit the variable with respect to which you are differentiating.
Aside: Compare this to what happens when you differentiate both sides with respect to some other independent parameter, say :
b. This is just a matter of plugging
Step-by-step explanation:
like if this was helpful
Answer:
![12-[20-2(6^2\div3\times2^2)]=88](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%3D88)
Step-by-step explanation:
So we have the expression:
![12-[20-2(6^2\div3\times2^2)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D)
Recall the order of operations or PEMDAS:
P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.
E: Within the parentheses, if exponents are present, do them before all other operations.
M/D: Multiplication and division next, whichever comes first.
A/S: Addition and subtraction next, whichever comes first.
(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)
Thus, we should do the operations inside the parentheses first. Therefore:
![12-[20-2(6^2\div3\times2^2)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D)
The parentheses is:

Square the 6 and the 4:

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

Therefore, the original equation is now:
![12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%5C%5C%3D12-%20%5B20-2%2848%29%5D)
Multiply with the brackets:
![=12-[20-96]](https://tex.z-dn.net/?f=%3D12-%5B20-96%5D)
Subtract with the brackets:
![=12-[-76]](https://tex.z-dn.net/?f=%3D12-%5B-76%5D)
Two negatives make a positive. Add:

Therefore:
![12-[20-2(6^2\div3\times2^2)]=88](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%3D88)