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denis23 [38]
3 years ago
7

What is the area of this polygon? Enter your answer in the box. units²

Mathematics
2 answers:
Gemiola [76]3 years ago
4 0

Answer:

The area of the polygon is 39\:units^2

Step-by-step explanation:

Sketch the polygon to obtain the figure in the attachment.

The polygon can then be divided into a rectangle and a triangle.

The area of the polygon

=|VE|\times |DE|+\frac{1}{2}\times |DE|\times |AM|

We use the absolute value method to find the lengths

=|3--2|\times |3--3|+\frac{1}{2}\times|3--3|\times |5-2|

=5\times 6+\frac{1}{2}\times 6\times 2

=30+9

=39\:units^2

marta [7]3 years ago
3 0

Answer:

The area of given polygon is 39 units² .

Step-by-step explanation:

It is given that the vertices of a 5-sided polygon on a coordinate plane are M(-5, 2), V(-2, 3), E(3, 3), D(3, -3) and R(-2,-3).

The composite figure has one rectangle and one triangle.

From the below figure it is clear that the length of the rectangle is 5 units and width of the rectangle is 6 units.

The area of a rectangle is

A=length\times width

A_1=5\times 6=30

The area of the rectangle is 30 units² .

From the below figure it is clear that the base of the triangle is 6 units and height of the triangle is 3 units.

The area of a triangle is

A=\frac{1}{2}\times base\times height

A_2=\frac{1}{2}\times 6\times 3=9

The area of the triangle is 9 units² .

The area of composite figure is

A=A_1+A_2

A=30+9=39

Therefore the area of given polygon is 39 units² .

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sineoko [7]

The construction crew took 3\frac{3}{8} days to build 4\frac{1}{2} miles of road.

Therefore, in 1 day, the crew built \frac{4\frac{1}{2} }{3\frac{3}{8} } miles of road

= \frac{\frac{9}{2} }{\frac{27}{8} } =\frac{9}{2}times\frac{8}{27}=\frac{4}{3} miles of road

Thus, the required rate is \frac{4}{3} miles or 1\frac{1}{3} miles per day.

5 0
3 years ago
What is the area of this? Please help
Slav-nsk [51]

Answer:

<u>364 cm²</u>

Step-by-step explanation:

Area of the figure :

  • Area (triangle) + Area (rectangle 1) + Area (rectangle 2) + Area (rectangle 3)
  • 1/2 x 20 x 14 + 12 x 9 + 7 x 3 + 19 x 5
  • 140 + 108 + 21 + 95
  • 248 + 21 + 95
  • 269 + 95
  • <u>364 cm²</u>

3 0
1 year ago
Read 2 more answers
Which expressions are equivalent??
Brilliant_brown [7]

<u>Given</u>:

The given expression is 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)

We need to determine the equivalent expression.

<u>Option A:</u> -1

Solving the expression, we get;

\frac{3}{2} x+14-\frac{3}{2} x+15

Simplifying, we get;

14+15=29

Thus, the expression 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right) is not equivalent to -1.

Hence, Option A is not the correct answer.

<u>Option B</u>: 29

Solving the expression, we get;

\frac{3}{2} x+14-\frac{3}{2} x+15

Simplifying, we get;

14+15=29

Thus, the expression 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right) is equivalent to 29.

Hence, Option B is the correct answer.

<u>Option C</u>: 2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]

Let us rewrite the given expression.

2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]

Thus, the expression 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right) is equivalent to 2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]

Thus, Option C is the correct answer.

<u>Option D</u>: 2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)

Rewriting the expression, we get;

2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]

Hence, the expression 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right) is equivalent not to 2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)

Thus, Option D is not the correct answer.

<u>Option E:</u> 2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)

Multiplying the terms within the bracket, we get;

2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)

Hence, the expression 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right) is equivalent to 2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)

Thus, Option E is the correct answer.

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Given csc A= 37/12 and that angle A is in Quadrant I, find the exact value of sec A in
vredina [299]

Answer:

Step-by-step explanation:

Below is the pic of how this would be set up in order to determine what it is you are looking for. The angle is set in QI, and since csc A is the reciprocal of sin, the ratio is hypotenuse over side opposite. Solve for the missing side using Pythagorean's Theorem:

37^2=12^2+b^2 and

1369 = 144 + b² and

1225 = b² so

b = 35

The sec ratio is the reciprocal of cos, so if cos is adjacent over hypotenuse, the sec is hypotenuse over adjacent, which is 37/35

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3 years ago
Below are the functions of y = |x| and y= |x| - 9 how are the functions related?
Liono4ka [1.6K]

sorry my brain is the size of a ant

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