So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Answer:
111
Step-by-step explanation:
Please mark brainliest
Answer:
21
Step-by-step explanation:
Use Pemdas.
Parentesis first so 5+4 = 9 and 8-6=2 so, 9X2=18+3=21
Answer:
n=12.5
Step-by-step explanation:
10/8=n/10
multiply the denominator and numerators 10 ad 10=100 divide by 8=12.5
Answer:
Step-by-step explanation:
