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2 years ago

9÷(-3)=what is the answer

Mathematics

2 answers:

Vera_Pavlovna [14]2 years ago

5 0

your answer is -3

i hope this helps

Tanzania [10]2 years ago

4 0

When dividing by a negative the answer is always gonna be a negative unless both numbers are negative

So first do 9/3

The answer is 3 because 3 goes into 9, 3 times

Since the 3 in the equation is negative

In the answer the 3 will also be negative

-3

To check your answer

If you multiply a negative by a negative the answer is going to be positive

So, -3 * -3 = 9

Your answer is correct

-3 is the answer

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Answer:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

Step-by-step explanation:

We are given the expression to be simplified:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}}$

Let us take common a term with a power of 5 from the numerator and the denominator of the given expression.

We know that:

$a^{p+q} = a^p \times a^q$

Let us use it to solve the powers of 5 in the given expression.

$\therefore$ we can write:

$5^{n+2} = 5^{n+1}\times 5= 5^n\times 5^{2}$

$5^{n+1} = 5^n\times 5$

The given expression becomes:

$\dfrac{5^{n+1} \times 5-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n}\times 5}$

Taking common $5^{n+1}$ from the numerator and

Taking common $5^{n}$ from the denominator

$\Rightarrow \dfrac{5^{n+1} (5-6)} {5^{n}(13-2\times5)}\\\Rightarrow \dfrac{5^{n+1} (-1)} {5^{n}(13-10)}\\\Rightarrow -\dfrac{5^{n+1}} {5^{n}\times3}\\\Rightarrow -\dfrac{5^{n}\times 5} {5^{n}\times3}\\\Rightarrow -\dfrac{5}{3}$

$\therefore$ The answer is:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

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