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3 years ago

Please help me with this. i don't understand it.

Mathematics

2 answers:

serg [7]3 years ago

5 0

Answer:

Step-by-step explanation:

1) Rectangular prism: l = 7.5 cm ; w = 12 cm ; h = 15.5cm

Volume of rectangular prism = l * w * h

Cubes: edge = 0.5cm

Volume of cube = edge *edge * edge

Number of cubes = Volume of rectangular prism ÷ Volume of a cube

$=\frac{7.5 * 12 * 15.5}{0.5*0.5*0.5}\\\\ = \frac{7.5 * 12 * 15.5*1000}{0.5 *0.5 *0.5 *1000}\\\\= \frac{75 * 12 *155 * 10}{5 * 5 * 5}\\\\= 3 * 12 * 31 * 10\\\\= 11160$

11160 cubes will fit in the prism.

2) Volume of prism = 7.5 * 12 * 15.5

= 1395 cm³

Vika [28.1K]3 years ago

4 0

Answer:

A. 11160 cubes B. 1395cm^3

Step-by-step explanation:

Volume= length x width x height

Its easiest to solve B. first and use it to solve A.

B. 7.5 x 12 x 15.5 = 1395cm^3 (volume of prism)

A. .5 x .5 x .5 = 1/8cm^3 (which is the volume of the cube)

1395 ÷ 1/8 = 11160

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7 0

3 years ago

Do not understand please help <br> Thank u

AysviL [449]

Answer:

43.4

Step-by-step explanation:

You will need to use the phythagoream therom, which is a² + b² = c². Plug the values in for the variables to get 7² + b² = 44², (c would equal the hypothenuse because the hypothenuse is the longest side of the triangle.) Square the values to get 49 + b² = 1936. Subtract 49 from both sides to get b² = 1887, then take the square root of both sides to get b = 43.4 (rounded to the nearest tenth.)

I am really sorry if I'm wrong, but have a good day/night! :)

6 0

3 years ago

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3 years ago

A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use of one particular cust

Fiesta28 [93]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given set of values

$321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320$

STEP 2: Write the formula for calculating the Standard deviation of a set of numbers

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ where\text{ }x_i\text{ are data points,} \\ \bar{x}\text{ is the mean} \\ \text{n is the number of values in the data set} \end{gathered}$

STEP 3: Calculate the mean

$\begin{gathered} \bar{x}=\frac{\sum ^{}_{}x_i}{n} \\ \bar{x}=\frac{\sum ^{}_{}(321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320)}{20} \\ \bar{x}=\frac{8453}{20}=422.65 \end{gathered}$

STEP 4: Calculate the Standard deviation

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ \sum ^{}_{}(x_i-\bar{x})^2\Rightarrow\text{Sum of squares of differences} \\ \Rightarrow10332.7225+657.9225+18591.3225+982.8225+2740.52251+9731.8225+3522.4225+18319.6225+2878.3225 \\ +8163.1225+1417.5225+3925.0225+1321.3225+386.1225+5677.6225+2953.9225+3800.7225 \\ +3209.2225+2565.4225+10537.0225 \\ \text{Sum}\Rightarrow108974.0275 \\ \\ S\tan dard\text{ deviation}=\sqrt[]{\frac{111714.55}{20-1}}=\sqrt[]{\frac{111714.55}{19}} \\ \Rightarrow\sqrt[]{5879.713158}=76.67928767 \\ \\ S\tan dard\text{ deviation}\approx76.68 \end{gathered}$

Hence, the standard deviation of the given set of numbers is approximately 76.68 to 2 decimal places.

STEP 5: Calculate the First and third quartile

$\begin{gathered} \text{IQR}=Q_3-Q_1 \\ \\ To\text{ get }Q_1 \\ We\text{ first arrange the data in ascending order} \\ \mathrm{Arrange\: the\: terms\: in\: ascending\: order} \\ 320,\: 321,\: 324,\: 360,\: 361,\: 366,\: 369,\: 372,\: 385,\: 397,\: 403,\: 454,\: 459,\: 475,\: 477,\: 482,\: 498,\: 513,\: 558,\: 559 \\ Q_1=(\frac{n+1}{4})th \\ Q_1=(\frac{20+1}{4})th=\frac{21}{4}th=5.25th\Rightarrow\frac{361+366}{2}=\frac{727}{2}=363.5 \\ \\ To\text{ get }Q_3 \\ Q_3=(\frac{3(n+1)}{4})th=\frac{3\times21}{4}=\frac{63}{4}=15.75th\Rightarrow\frac{477+482}{2}=\frac{959}{2}=479.5 \end{gathered}$

STEP 6: Find the Interquartile Range

$\begin{gathered} IQR=Q_3-Q_1 \\ \text{IQR}=479.5-363.5 \\ \text{IQR}=116 \end{gathered}$

Hence, the interquartile range of the data is 116

3 0

1 year ago

What is 6➗2+5+2✖3=24 in parenthesis

Juliette [100K]

(6÷2)+(5+2×3)=24
I got this so this is the answer

;D

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3 years ago