The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
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The lines that intersect is B
Answer:
option D :
f(-8) = -2 ; f(4) = 3
Step-by-step explanation:
f(-8) = ³√-8 = -2
f(4) = 3 (the constant function)
Answer:
(x+2) + x + (x+4) = 2(1/2) + 2(x+3)
Step-by-step explanation:
They are equal to each other and the rectangle has 2x more perimeter
The triangle would be divided in half from that rectangle.
Sorry If this is confusing I am not very good at explaining things.
Radius is 3 And diameter 3×2
