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Eduardwww [97]
3 years ago
5

What is least common multiple of 16 and 76​

Mathematics
2 answers:
olasank [31]3 years ago
6 0

Answer:

lcm(76,16) = 304

Step-by-step explanation:

The multiples of 76 are … , 228, 304, 380, ….

The multiples of 16 are …, 288, 304, 320, …

The common multiples of 76 and 16 are n x 304, intersecting the two sets above, n\neq 0 \thinspace\in\thinspace\mathbb{Z}n  



​  

=0∈Z.

Shtirlitz [24]3 years ago
3 0

Answer:

304

Step-by-step explanation:

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Step-by-step explanation:

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Find the missing angle..? x=?
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Answer:

x = 95°

Step-by-step explanation:

x and 95 are vertical angles and congruent, thus

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Hi please can you help me this is a new topic and I’m very confused
olchik [2.2K]

Answer: the large jar is cheaper

Step-by-step explanation:

If you divide the £1.54 by 440g and £1.26 by 340g, you'll find which one is cheaper per gram :

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8 0
2 years ago
It takes 8 hours for 4 men to paint a room.
eimsori [14]

Answer:

16 men would be needed to paint the room in 2 hours

Step-by-step explanation:

We can use proportion to solve the problem given, but first we need to determine whether it is a direct or indirect proportion.

If the number of men are increase, the time taken to do the work will decrease, If the number of men are decrease, the time taken to do the work will increase. Therefore, this is an indirect proportion.

We are going to arrange the data inversely.

Let x be the number of men needed to paint the room in two hours

8 hours =  2 hours

    x        = 4 men

Cross-multiply

2×x = 8×4

2x = 32

Divide both-side of the equation by 2

2x/2 = 32/2

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16 men would be needed to paint the room in 2 hours

7 0
3 years ago
Which equation has the solutions x=1+or-square root of 5?
stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> x^{2}+2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=-4+1

x^{2}+2x+1=-3

Rewrite as perfect squares

(x+1)^{2}=-3

(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i

therefore

case a) is not the solution of the problem

<u>case b)</u> x^{2}-2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=-4+1

x^{2}-2x+1=-3

Rewrite as perfect squares

(x-1)^{2}=-3

(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i

therefore

case b) is not the solution of the problem

<u>case c)</u> x^{2}+2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=4+1

x^{2}+2x+1=5

Rewrite as perfect squares

(x+1)^{2}=5

(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}

therefore

case c) is not the solution of the problem

<u>case d)</u> x^{2}-2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=4+1

x^{2}-2x+1=5

Rewrite as perfect squares

(x-1)^{2}=5

(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

x^{2}-2x-4=0

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