Answer:
(a) 1.353 x 10^9
Step-by-step explanation:
Jumping 9 places back to obtain standard form
Answer:
x = 5
Step-by-step explanation:
2x -4 = 6
Add +4 on both sides
2x = 10
Divide by 2
x = 5
Answer:
∠BAD=20°20'
∠ADB=34°90'
Step-by-step explanation:
AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.
Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus
∠BOD+∠BDO+∠DBO=180°
∠BDO+∠DBO=180°-110°20'=69°80'
∠BDO=∠DBO=34°90'
So ∠ADB=34°90'
Angles BOD and BOA are supplementary (add up to 180°), so
∠BOA=180°-110°20'=69°80'
In right triangle ABO,
∠ABO+∠BOA+∠OAB=180°
90°+69°80'+∠OAB=180°
∠OAB=180°-90°-69°80'
∠OAB=20°20'
So, ∠BAD=20°20'
<span>Actually the above equation can be solved by following the below steps to fins the value of x
Step1: 3(x-k)/w=4
Step 2: (3x-3k)/w=4
Step 3: (3x-3k)=4w
Step 4: 3x=4w+3k
So hence therefore by following the above steps we can conclude that the value of x is
Step 5: x=(4w+3k)/3</span>