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kotykmax [81]
3 years ago
11

C.

Mathematics
1 answer:
Ulleksa [173]3 years ago
6 0

(94.50 - 18.50) ÷ f = a

f=family members

a=answer

I don't know how many family members there are, but you would just replace f with the amount.

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Can someone answer this for me.
Marina CMI [18]

Answer:

A)  slope is 2/5 (positive slope)

B) slope is -2/6 (negative slope)

C) Yes, with different points, the slope remains the same.

3 0
2 years ago
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1/3 radical 176xy to the 8th power​
Tanya [424]

Answer:

Remove all perfect squares from inside the square root. ... I think it's about eighth or ninth grade. ... so if you have the cube root of the square root of (x-5) =2, you get ((x-5)^(1/2))^1/3 = 2, power to power requires multiplication, so (x-5)^1/6 = 2, ...

Missing: 176 ‎xy

5 0
2 years ago
What is the simplified form of x+3/4+x+2/4
Savatey [412]
Hey there! :D

Since all the terms are being added together, and there is a common denominator with the fractions, we can just add them.

x+x= 2x  3/4+2/4= 5/4

2x+5/4

2x+1.25<== simplest form

I hope this helps!
~kaikers
7 0
3 years ago
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HELP PLS!!! I GIVE BRAINLIEST
emmainna [20.7K]

Based on the multiplication property of equality, the statement that completes the proof is: C. CD = b(sin A) and CD = a(sin B).

<h3>What is the Multiplication Property of Equality?</h3>

The multiplication property of equality is given as, if a/b = y, then a = yb. Both sides of the equation is multiplied by the same value.

In step 5 where the multiplication property of equality is applied, we would have:

sin(A) = CD/b

Multiply both sides by b

sin(A) × b = CD/b × b

b(sin A) = CD

CD = b(sin A)

This same property is applied to sin B = CD/a to get CD = a(sin B).

Therefore, the missing statement is: C. CD = b(sin A) and CD = a(sin B).

Learn more about the multiplication property of equality on:

brainly.com/question/1978763

#SPJ1

8 0
1 year ago
Given the function f(x)= 14x^2 + 5x - 1 answer the question if you could change the 14 to any other number, but the rest has to
polet [3.4K]
This is a polynomial of degree 2, and remember that complex roots always come in pairs; therefore, in a second degree polynomial you can only have 0 real roots and 2 complex roots, or 2 real roots and 0 complex roots. There is no way you can have 1 real root and 1 complex root because, as stated before, complex (non-real) roots always come in pairs; so the only way of having 1 real root is dumping the polynomial of degree 2 (14 x^{2}) by changing the 14 to 0. That way we'll left with f(x)=5x-1 which only has one real root:
0=5x-1
5x=1
x= \frac{1}{5}

7 0
3 years ago
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