Answer:
9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch
Step-by-step explanation:
Diameter of reamed hole = 0.278 inch
Radius of reamed hole = 
Surface area of reamed hole = 
Surface area of reamed hole = 
Surface area of reamed hole = 0.06066794
Diameter of pin = 
Radius of pin =
Surface area of pin = 
Since the surface area of pin is more than the surface area of hole .
So, a 9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch
Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
The temperature at 5 am was -3 degrees
12-15=-3
Answer:
3/4
Because 6 are not white so 6/8 and divide each by 2
6 divided by 2 = 3
8 divided by 2 = 4
= 3/4
Step-by-step explanation:
Hope this helps her!!!
