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Mekhanik [1.2K]
2 years ago
14

Practice: triangle sum theorem on a piece of paper solve for the variable , then find the missing angles

Mathematics
1 answer:
MariettaO [177]2 years ago
3 0
1) x=-3. The missing angle is 71 degrees
2) x=45. The missing angles are 90 and 45 degrees.
3) x=40. The missing angles are 40 and 100 degrees
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What is the geometric mean between 7 and 12
Tresset [83]

Answer:

Geometric Mean = 9.17

Step-by-step explanation:

Here,

a = 7

b = 12

Geometric mean = root(ab)

= root( 7 x 12)

= root(84)

= 9.17

6 0
2 years ago
Read 2 more answers
Convert each percentage into a decimal and match them with the appropriate result.
skad [1K]

Answer:

32% = 0.32

50% = 0.50

34% = 0.34

Step-by-step explanation:

0.32 = 32%

0.50 = 50%

0.34 = 34%

P.S Can I have brainliest?

5 0
2 years ago
Read 2 more answers
Does someone get this?
Anna11 [10]

Answer:

C.

Explication:

It wants you to determined which angle is bigger out of two of the angles.

Angle A. is 3.9 inches plus 7.9 inches

Angle B. is 3.9 inches plus 4.2 inches

Angle C. is 7.9 inches plus 4.2 inches

4 0
3 years ago
Read 2 more answers
Is (a-3)(2a^2 + 3a + 3) equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)
vovikov84 [41]
<h3>Answer: Yes they are equivalent</h3>

==============================================

Work Shown:

Expand out the first expression to get

(a-3)(2a^2 + 3a + 3)

a(2a^2 + 3a + 3) - 3(2a^2 + 3a + 3)

2a^3 + 3a^2 + 3a - 6a^2 - 9a - 9

2a^3 + (3a^2-6a^2) + (3a-9a) - 9

2a^3 - 3a^2 - 6a - 9

Divide every term by 2 so we can pull out a 2 through the distributive property

2a^3 - 3a^2 - 6a - 9 = 2(a^3 - 1.5a^2 - 3a - 4.5)

This shows that (a-3)(2a^2 + 3a + 3) is equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)

4 0
3 years ago
Read 2 more answers
A project being analyzed by PERT has 38 activities, 16 of which are on the critical path. If the estimated time along the critic
dolphi86 [110]

Answer:

required probability is .3446

Step-by-step explanation:

It is given that most expected time of completion = 90 days

Variance = 25

We know that

\sigma =\sqrt{Variance}\\\\\sigma =\sqrt{25}\\\sigma =5

Thus the standard normal deviate is given by

Z=\frac{X-\bar{X}}{\sigma }

Applying values we get

Z=\frac{88-90}{5}\\\\Z=-0.4

Using the standard table for Z we have probability corresponding to Z = -0.4 equals 0.3446

Thus required probability is .3446

3 0
3 years ago
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