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3 years ago

Please help me with the question please ASAP ASAP please please ASAP please please help

Mathematics

2 answers:

viva [34]3 years ago

6 0

Answer:

The tree is 8 foot long

hope this helps

good day mate

irakobra [83]3 years ago

4 0

Answer:

Step-by-step explanation:

12:6 = x:4

2:1 = x:4

x=8

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Find the average distance each data value in the set is from the mean.

olga55 [171]

To find the mean, you have to add all of the data together and divide by the amount of data sets there are. 2010+2002+2005+2007+2001=10025
10025 divided by 5 sets of data is 2005.
The mean or average is 2005

7 0

3 years ago

12x+7<-11 or 5x-8>40

DaniilM [7]

Answer:

Step-by-step explanation:

Given

12x + 7 < - 11 or 5x - 8 > 40

Solve each inequality

12x + 7 < - 11 ( subtract 7 from both sides )

12x < - 18 ( divide both sides by 12 )

x < - $\frac{3}{2}$

5x - 8 > 40 ( add 8 to both sides )

5x > 48 ( divide both sides by 5 )

x > $\frac{48}{5}$

Solution is

x < - $\frac{3}{2}$ or x > $\frac{48}{5}$ → A

6 0

3 years ago

Is 1.403 bigger than 1.4

NISA [10]

Yes. 1.403 is 0.003 more than 1.4 .

5 0

4 years ago

Read 2 more answers

Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2

r-ruslan [8.4K]

Answer:

The value of given expression is $\frac{21}{128}$ .

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

$q=1-p=1-\frac{1}{2}=\frac{1}{2}$

The given expression is

$C(n,x)p^xq^{n-x}$

It can be written as

$^nC_xp^xq^{n-x}$

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

$^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}$

$\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}$

$\frac{7!}{2!5!}(\frac{1}{2})^{2+5}$

$\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}$

$21(\frac{1}{2})^{7}$

$\frac{21}{128}$

Therefore the value of given expression is $\frac{21}{128}$ .

7 0

3 years ago

Susan has $65 in her savings account. Her friend coco has &119 in her savings account. Susan plans to add $23 per week. How

uranmaximum [27]

Answer:

After 10 weeks, Susan will have $295 and CiCi will have $259.

Step-by-step explanation:

Susan: y= 65+23x

CiCi: y = 119+14x

65+23(6)=203

119+14(6)=203

After 6 weeks, Susan and CiCi will both have $203 in their accounts.

65+23(10)=295

119+(14)(10)=259

Therefore, After 10 weeks, Susan will have $295 and CiCi will have $259.

4 0

3 years ago