<span>1. In a circle, if two chords are equal in measure, then their corresponding minor arcs are equal in measure.
2. The relationship between equality of the measures of chords and equality of the measures of their corresponding minor arcs.
3. A diameter that is perpendicular to a chord.
4. In a circle, the relationship between two chords being equal in measure and being equidistant.
5. A circle with two minor arcs equal in measure
6. A circle with a diameter perpendicular to a chord.
I don't know if this will help you but maybe it will</span>
Answer:
The directional bearing of the boat is N 30º E
Step-by-step explanation:
Let 
, where 
is the vector velocity. Given that such vector is represented in rectangular, a positive value in the first component is the value of the vector in the east direction, whereas a positive value in the second component is in the north direction. The directional bearing of the boat (
), measured in sexagesimal degrees, is determined by trigonometrical means:
(1)
If we know that 
and 
, then the directional bearing of the boat is:
In consequence, we conclude that the direction bearing of the boat is 30 degrees to the East from the North (N 30º E).
Answer:
8 servings
Step-by-step explanation:
Take the total ounces and divide by the number of ounces per serving
42/5 =8.4
Round down since we don't want to short someone on their soup
8
Answer:
It won't be the same shape and length and width I think
Step-by-step explanation:
ANSWER:
x = 10 / 3
y = 0
STEP-BY-STEP EXPLANATION:
We will be using simultaneous equations to solve this problem. Let's first establish the two equations which we will be using.
Equation No. 1 -
- 6x - 14y = - 20
Equation No. 2 -
- 3x - 7y = - 10
First, we will make ( x ) the subject in the first equation and simplify accordingly.
Equation No. 1 -
- 6x - 14y = - 20
- 6x = - 20 + 14y
x = ( - 20 + 14y ) / - 6
x = ( - 10 + 7y ) / - 3
From this, we will make ( y ) the subject in the second equation and substitute the value of ( x ) from the first equation into the second equation to solve for ( y ) accordingly.
Equation No. 2 -
- 3x - 7y = - 10
- 7y = - 10 + 3x
- 7y = - 10 + 3 [ ( - 10 + 7y ) / - 3 ]
- 7y = - 10 + [ ( - 30 + 21y ) / - 3 ]
- 7y = - 10 + ( 10 - 7y )
- 7y = - 7y
- 7y + 7y = 0
0y = 0
y = 0
Using this, we will substitute the value of ( y ) from the second equation into the first equation to solve for ( x ) accordingly.
x = ( - 10 + 7y ) / - 3
x = [ - 10 + 7 ( 0 ) ] / - 3
x = [ - 10 + 0 ] / - 3
x = - 10 / - 3
x = 10 / 3
