T-2(3-2t)=2t+9
t-6+4t=2t+9
5t-6=2t+9
5t-2t=9+6
3t=15
t=15/3
t=5
Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
Hello there! The solution of your question has been given below.
<h3>Solution:</h3>

<h3>Answer:</h3>
Option B.

Use a proportion:
10 cm^3 / 1.2 grams = 22 cm^3 / x
solve for x
x = 2.64 grams
If this helped you, please list me as brainliest!
Plug In The Values.
-(-5)/2 * 4
-(-5) = 5
2 * 4 = 8
So, The Answer Is 5/8