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ad-work [718]
3 years ago
6

PLEASE HELP!! MY GRADE DEPENDS ON IT. Find the following measures of the arc or angle in the diagram:

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0
M is 23 even 45 56 79
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Y’all please help me with this I don’t understand
Yanka [14]

Answer: I believe it’s 8

Step-by-step explanation:

It’s 13 minus 5

3 0
3 years ago
Read 2 more answers
Devante went to the college traveling 15 mph and returned home traveling 6 mph. if the total trip took 7 hours, how long did dev
telo118 [61]
If it took t hours to travel to college then it took 7-t to return home.
The distance travelled is the same so 15t=6(7-t), 15t=42-6t, 21t=42, t=2 hours.
So travel to college took 2 hours and it took 5 hours to return home.
7 0
4 years ago
Please help
ElenaW [278]
20 days
x=number of days vacation
y=daily expenses
xy=1100
(x+2)(y-5)=1100
*******
xy-5x+2y-10=1100
xy-5x+2y=1110
y=1100/x
x(1100/x)-5x+2(1100/x)=1110
1100-5x+(2200/x)=1110
-5x+(2200/x)=10
-5x^2 + 2200 = 10x
-x^2 + (440) = 2x
x^2 - 440 + 2x = 0
(x+22)(x-20)=0
x=-22,20
only take the positive answer because the negative answer doesn't make sense in the question
so the answer is 20
****
I might be wrong; this question probation should've been this hard so I might have taken a wrong turn somewhere. feel free to double check my work
3 0
3 years ago
in 2012, the population of a city was 63,000. by 2017, the population was reduced to approximately 54,100. identify any equation
Akimi4 [234]

Answer:

<em></em>f(x) = 63000(0.97)^x<em></em>

<em></em>

Step-by-step explanation:

Given

f(0) = 63000 ---x = 0, in 2012

f(5) = 54100 -- x = 5, in 2017

Required

Select all possible equations

Because there is a reduction in the population, as time increases; the rate must be less than 1.

An exponential function is represented as:

f(x) = ab^x

Where

b = rate

rate > 1 in options (a) and (b) i.e. 1.03

This implies that (a) and (b) cannot be true

For option (c), we have:

f(x) = 63000(0.97)^x

Set x = 0

f(0) = 63000(0.97)^0 = 63000*1=63000\\

Set x = 5

f(5) = 63000(0.97)^5 = 63000*0.8587=54098.1 \approx 54100

<em>This is true because the calculated values of f(0) and f(5) correspond to the given values</em>

For option (d), we have:

f(x) = 52477(0.97)^x

Set x = 0

f(0) = 52477(0.97)^0 - 52477* 1 = 52477

<em>This is false because the calculated value of f(0) does not correspond to the given value</em>

For option (e), we have:

f(x) = 63000(0.97)^\frac{1}{5x}

Set x = 0

f(0) = 63000(0.97)^\frac{1}{5*0} = 63000(0.97)^\frac{1}{0} =undefined

<em>This is false because the f(x) is not undefined at x = 0</em>

For option (f), we have:

f(x) = 52477(0.97)^{5x

Set x = 0

f(0) = 52477(0.97)^{5*0} = 52477(0.97)^0 =52477*1= 52477

<em>This is false because the calculated value of f(0) does not correspond to the given value</em>

<em>From the computations above, only (c) </em>f(x) = 63000(0.97)^x<em> is true</em>

4 0
3 years ago
What is the slope of the linear function that passes through the points (2, 11) and (0,<br> 5)?
vekshin1

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4 0
3 years ago
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